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27 tháng 7 2020

=2.25.7.9/10.15.21

rut gon:

=9/9

=1

27 tháng 7 2020

 \(\frac{2.5^2.7.9}{10.15.21}\)

\(=\frac{2.5.5.7.3.3}{2.5.5.3.7.3}\)

\(=\frac{1}{1}\)

\(=1\)

Chúc bạn học tốt!!!

`@` `\text {Ans}`

`\downarrow`

\(1793\cdot\left(x\div1792\right)=0\)

`\Rightarrow x \div 1792 = 0 \div 1793`

`\Rightarrow x \div 1792 = 0`

`\Rightarrow x = 0. 1792`

`\Rightarrow x = 0`

Vậy, `x = 0.`

18 tháng 7 2023

\(1793.\left(x:1792\right)=0\)

\(=>x:1792=0:1793\)

\(=>x:1792=0\)

\(=>x=0.1792\)

\(=>x=0\)

10 tháng 5 2019

\(A=\frac{4}{2.5}+\frac{4}{5.8}+\frac{4}{8.11}+...+\frac{4}{65.68}\)

\(A=\frac{4}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{65.68}\right)\)

\(A=\frac{4}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{65}-\frac{1}{68}\right)\)

\(A=\frac{4}{3}.\left[\frac{1}{2}+\left(\frac{1}{5}-\frac{1}{5}\right)+\left(\frac{1}{8}-\frac{1}{8}\right)+...+\left(\frac{1}{65}-\frac{1}{65}\right)-\frac{1}{68}\right]\)

\(A=\frac{4}{3}.\left[\frac{1}{2}-\frac{1}{68}\right]\)

\(A=\frac{4}{3}.\frac{33}{68}\)

\(A=\frac{11}{17}\)

~ Hok tốt ~

10 tháng 5 2019

\(A=\frac{4}{3}\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+....+\frac{1}{65}-\frac{1}{68}\right)\)

     \(=\frac{4}{3}\left(\frac{1}{2}-\frac{1}{68}\right)\)

       \(=\frac{4}{3}\times\frac{33}{68}=\frac{11}{17}\)

19 tháng 7 2023

a/

\(A=1.2+1.2+2.3+2.2+3.4+3.2+...+66.67+66.2=\)

\(=\left(1.2+2.3+3.4+...+66.67\right)+2\left(1+2+3+...+66\right)\)

Đặt

\(B=1+2+3+...+66=\dfrac{66\left(1+66\right)}{2}=2211\)

Đặt 

\(C=1.2+2.3+3.4+...+66.67\)

\(3C=1.2.3+2.3.3+3.4.3+...+66.67.3=\)

\(=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+66.67.\left(68-65\right)=\)

\(=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-...-65.66.67+66.67.68=\)

\(=66.67.68\Rightarrow C=\dfrac{66.67.68}{3}=22.67.68\)

\(\Rightarrow A=C+2B\) Bạn tự tính nhé

b/

\(B=2\left(1.50+2.49+3.48+...+25.26\right)=\)

Ta có

\(C=1.50+2.49+3.48+...+25.26=\)

\(\left(50-49\right).50+\left(50-48\right).49+\left(50-47\right).48+...+\left(50-25\right).26=\)

\(=50.50-49.50+50.49-48.49+50.48-47.48+50.26-25.26=\)

\(=50.\left(26+27+28+...+50\right)-\left(25.26+26.27+27.28+...+49.50\right)\)

Ta có

\(D=26+27+28+...+50=\dfrac{25.\left(26+50\right)}{2}=950\)

Ta có

\(E=25.26+26.27+27.28+...+49.50\)

\(3E=25.26.3+26.27.3+27.28.3+...+49.50.3=\)

\(=25.26.\left(27-24\right)+26.27.\left(28-25\right)+...+49.50.\left(51-48\right)=\)

\(=-24.25.26+25.26.27-25.26.27+26.27.28-...-48.49.50+49.50.51=\)

\(=49.50.51-24.25.26\)

\(\Rightarrow E=\dfrac{49.50.51-24.25.26}{3}\)

\(\Rightarrow C=50D-E\)

\(B=2C\)

Bạn tự tính nhé

16 tháng 5 2016

S = 1/3 . (1/2 - 1/5 + 1/5 - 1/8 + ... + 1/17 - 1/20)

   = 1/3 . (1/2 - 1/20)

   = 1/3 . 9/20

   = 3/20

16 tháng 5 2016

\(3S=\frac{5-2}{2.5}+\frac{8-5}{5.8}+\frac{11-8}{8.11}+...+\frac{20-17}{17.20}\)

\(3S=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}=\frac{1}{2}-\frac{1}{20}=\frac{9}{20}\)

\(S=\frac{9}{20}:3=\frac{3}{20}\)

24 tháng 7 2019

\(\frac{1}{2.5}+\frac{1}{5.8}+...+\frac{1}{\left(3n-1\right)\left(3n+2\right)}\)

\(=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{\left(3n-1\right)\left(3n+2\right)}\right)\)

\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{3n-1}-\frac{1}{3n+2}\right)\)

\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{3n+2}\right)\)

\(=\frac{1}{3}.\frac{3n}{2.\left(3n+2\right)}\)

\(=\frac{n}{2\left(3n+2\right)}\)

15 tháng 4 2021

Đặt A = \(\frac{1}{2.5}+\frac{1}{5.8}+...+\frac{1}{23.26}+\frac{1}{26.29}\)
     3A = \(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{23.26}+\frac{3}{26.29}\)
          = \(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{23}-\frac{1}{26}+\frac{1}{26}-\frac{1}{29}\)
          = \(\frac{1}{2}-\frac{1}{29}\)\(=\frac{27}{58}\)
     A = \(\frac{27}{58}:3=\frac{9}{58}\)
 

15 tháng 4 2021

\(\frac{1}{2.5}+\frac{1}{5.8}+...+\frac{1}{23.26}+\frac{1}{26.29}=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{23.26}+\frac{3}{26.29}\right)\)

\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{23}-\frac{1}{26}+\frac{1}{26}-\frac{1}{29}\right)=\frac{1}{3}\left(\frac{1}{2}-\frac{1}{29}\right)\)

\(=\frac{1}{3}.\frac{27}{58}=\frac{9}{58}\)

29 tháng 10 2023

( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2

( 19x + 2.52 ) : 14 = 52- 4 2

( 19x + 2.52 ) : 14 = 25- 16

( 19x + 2.52 ) : 14 =9

( 19x + 50 ) : 14 =9

 19x + 50=9 . 14

 19x + 50=126

19x=126-50

19x=76

x=76:19

x=4

29 tháng 10 2023

(19x + 2.5²) : 14 = (13 - 8)² - 4²

(19x + 2.25) : 14 = 5² - 16

(19x + 50) : 14 = 25 - 16

(19x + 50) : 14 = 9

19x + 50 = 9 . 14

19x + 50 = 126

19x = 126 - 50

19x = 76

x = 76 : 19

x = 4