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\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=4,75-0,37+0,125-1,28-2,5+\frac{37}{12}\)
\(=0,725+\frac{37}{12}\)
\(=\frac{457}{120}\)
\(\left(4\frac{3}{4}+\frac{1}{8}+3\frac{1}{12}\right)-\left(0,37+1,28+2,25\right)\)
\(=7\frac{23}{24}-4,15\)
\(=7\frac{23}{24}-4\frac{3}{20}\)
\(=3\frac{97}{120}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(4\frac{3}{4}+\left(-0,37\right)+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=\frac{19}{4}+\left(-\frac{83}{20}\right)+\frac{37}{12}=\frac{3}{5}+\frac{37}{12}=\frac{221}{60}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{7}{2}=\left(\frac{19}{4}-\frac{37}{100}-\frac{32}{25}\right)+\left(\frac{7}{2}-\frac{5}{2}\right)+\frac{1}{8}=\frac{31}{10}+1+\frac{1}{8}=\frac{169}{40}\)
a: \(=\dfrac{17}{4}-\dfrac{37}{100}+\dfrac{1}{8}-\dfrac{32}{25}-\dfrac{5}{2}+\dfrac{7}{2}\)
\(=\dfrac{35}{8}+\dfrac{8}{8}-\dfrac{37}{100}-\dfrac{128}{100}\)
\(=\dfrac{43}{8}-\dfrac{165}{100}=\dfrac{149}{40}\)
b: \(=\left(\dfrac{22\cdot26+3\cdot10-65}{130}\right):\left(\dfrac{4\cdot22-2\cdot26+3\cdot143}{286}\right)\)
\(=\dfrac{537}{130}\cdot\dfrac{286}{465}=\dfrac{1969}{775}\)
Ta có:
\(\text{4/3/4+(-0,37)+1/8+(-1,28)+(-2,5)+3/1/12}\)
\(=4:4:3-0,37+1:8-1,28-2,5+3:1:12\)
\(=\frac{1}{3}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{1}{4}\)
\(=\frac{200}{600}-\frac{222}{600}+\frac{75}{600}-\frac{768}{600}-\frac{1500}{600}+\frac{150}{600}\)
\(=\frac{200-222+75-768-1500+150}{600}\)
\(=-\frac{2065}{600}\)
\(=-\frac{413}{120}\)
= 19/4 - 0,37 + 1/8 - 1,28 - 2,5 + 37/12
= 19/4 - 37/100 + 1/8 - 32/25 - 5/2 + 37/12
= 219/50 + (-231/200) - 67/12
= 129/40 - 67/12
=(-283/120)
bạn k cho mình đi làm ơn đó
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
\(=\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
\(=\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{2500}{1000}+\frac{37}{12}\)
\(=\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
\(=\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=\frac{457}{120}=3\frac{97}{120}\)
--Good luck--