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\(b,\left(\sqrt{1\frac{9}{16}-\sqrt{\frac{9}{16}}}\right):5\)
\(=\left(\sqrt{\frac{25}{16}-\frac{3}{4}}\right):5\)
\(=\sqrt{\frac{13}{16}}:5\)
\(=\frac{\sqrt{13}}{4}:5\)
\(=\frac{\sqrt{13}}{20}\)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}-\frac{3}{2}}\)
\(=7+\sqrt{\frac{1}{16}}\)
\(=7+\frac{1}{4}\)
\(=7\frac{1}{4}=\frac{29}{4}\)
\(\sqrt{\left(-7\right)^2}\)+ \(\sqrt{\frac{25}{16}}\)
= 7 +\(\frac{5}{4}\)
= \(8\frac{1}{4}\)
=\(\frac{33}{4}\)
\(\sqrt{\left(-7\right)^2}\) + \(\sqrt{\frac{25}{16}}\) - \(\frac{3}{2}\)
= 7 + \(\frac{5}{4}\) - \(\frac{3}{2}\)
= \(\frac{33}{4}\) - \(\frac{3}{2}\)
= \(\frac{27}{4}\)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\\ =7+\frac{5}{4}-\frac{3}{2}\\ =\frac{28}{4}+\frac{5}{4}-\frac{6}{4}\\ =\frac{28+5-6}{4}=\frac{27}{4}\)
= 7 + 5/4 - 1/2
= 28/4 + 5/4- 6/4
= 28 + 5 - 6/4
=27/4
chuc ban hc tot
\(\sqrt{\left(-7^2\right)}+\sqrt{\frac{25}{16}}-\frac{3}{2}\)
\(=\sqrt{49}+\sqrt{\left(\frac{5}{4}\right)^2}-\frac{3}{2}\)
\(=7+\frac{5}{4}-\frac{3}{2}\)
\(=\frac{27}{4}\)