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17 tháng 11 2018

 (1.09 - 0,29) × 1,25 = 0,8 × 1,25=1

(18.9 -16,65) × 88,8888888889 = 2,25 × 88,8888888889= 200

1

200

4 tháng 7 2016

\(A=\left[0,8.7\left(0,8\right)^2\right].\left(1,25.7-\frac{4}{5}.1,25\right)+31,64\)

  \(=0,8.\left(7+0,8\right).1,25.\left(7-0,8\right)+31,64\)

  \(=0,8.7,8.1,25.6,2+31,64\)

  \(=6,24.7,75+31,64\)

   \(=48,36+31,64=80\)

\(B=\frac{\left(1,09-0,29\right).\frac{5}{4}}{\left(18,9-16,65\right).\frac{8}{9}}=\frac{0,8.1,25}{2,25.\frac{8}{9}}=\frac{1}{2}\)

\(A:B=80:\frac{1}{2}=160\)

Vậy A gấp 160 lần B.

     

27 tháng 8 2019

\(A=\left[0,8\cdot7+(0,8)^2\right]\cdot\left[1,25\cdot7-\frac{4}{5}\cdot1,25\right]-47,86\)

\(=0,8\cdot(7+0,8)\cdot1,25\cdot(7-0,8)-47,86\)

\(=0,8\cdot7,8\cdot1,25\cdot6,2-47,86\)

\(=48,36-47,86=0,5\)

\(B=\frac{(1,09-0,29)\cdot\frac{5}{4}}{(18,9-16,65)\cdot\frac{8}{9}}=\frac{0,8\cdot1,25}{2,25\cdot\frac{8}{9}}=\frac{1}{2}\)

\(A:B=0,5:\frac{1}{2}=\frac{1}{2}:\frac{1}{2}=\frac{1}{2}\cdot2=1\)

A gấp 1 lần B

27 tháng 8 2019

hghghgjhefghj

22 tháng 7 2015

\(1\frac{1}{3}.1\frac{1}{4}.1\frac{1}{5}.1\frac{1}{6}.1\frac{1}{7}.1\frac{1}{8}.1\frac{1}{9}.1\frac{1}{10}.1\frac{1}{11}\)

\(=\frac{4}{3}.\frac{5}{4}.\frac{6}{5}.\frac{7}{6}.\frac{8}{7}.\frac{9}{8}.\frac{10}{9}.\frac{11}{10}.\frac{12}{11}\)

\(=\frac{12}{3}=4\)

11 tháng 10 2016

\(B=\frac{\left(1,09-0,29\right).1\frac{1}{4}}{\left(18,9-16\frac{13}{20}\right).\frac{8}{9}}=\frac{0,8.\frac{5}{4}}{\left[\left(18+0,9\right)-\left(16+\frac{13}{20}\right)\right].\frac{8}{9}}\)

\(B=\frac{\frac{4}{5}.\frac{5}{4}}{\left(18+\frac{9}{10}-16-\frac{13}{20}\right).\frac{8}{9}}\)

\(B=\frac{1}{\left[\left(18-16\right)+\left(\frac{9}{10}-\frac{13}{20}\right)\right].\frac{8}{9}}\)

\(B=\frac{1}{\left(2+\frac{1}{4}\right).\frac{8}{9}}\)

\(B=\frac{1}{\frac{9}{4}.\frac{8}{9}}=\frac{1}{2}\)

11 tháng 10 2016

thanks

17 tháng 10 2016

a) \(\frac{7}{15}+\frac{9}{10}+\frac{8}{15}-\frac{-1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\frac{7}{15}+\frac{9}{10}+\frac{8}{15}+\frac{1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\left(\frac{7}{15}+\frac{8}{15}\right)+\left(\frac{9}{10}+\frac{1}{10}\right)-2+\frac{1}{157}\)

\(=1+1-2+\frac{1}{157}\)

\(=2-2+\frac{1}{157}\)

\(=0+\frac{1}{157}=\frac{1}{157}\)

b) \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\frac{-12}{13}\)

\(=\frac{1}{13}+\frac{16}{7}+\frac{1}{35}-\frac{9}{7}+\frac{12}{13}\)

\(=\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{16}{7}-\frac{9}{7}\right)+\frac{1}{35}\)

\(=1+1+\frac{1}{35}\)

\(=2+\frac{1}{35}\)

\(=\frac{70}{35}+\frac{1}{35}=\frac{71}{35}\)