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\(a,\Rightarrow\left(4x-1\right)^2=25=5^2=\left(-5\right)^2\\ \Rightarrow\left[{}\begin{matrix}4x-1=5\\4x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-1\end{matrix}\right.\\ b,\Rightarrow2^x\left(1+2^3\right)=144\\ \Rightarrow2^x=144:9=16=2^4\Rightarrow x=4\\ c,\Rightarrow3^{2x+3}=3^{2\left(x+3\right)}\\ \Rightarrow2x+3=2x+6\Rightarrow0x=3\left(vô.lí\right)\\ \Rightarrow x\in\varnothing\)
a: Ta có: \(2^{x-1}=32\)
\(\Leftrightarrow x-1=5\)
hay x=6
b: Ta có: \(3^{2x+1}=81\)
\(\Leftrightarrow2x+1=4\)
\(\Leftrightarrow2x=3\)
hay \(x=\dfrac{3}{2}\)
c: Ta có: \(2^x-26=6\)
\(\Leftrightarrow2^x=32\)
hay x=5
d: Ta có: \(27\cdot3^x=243\)
\(\Leftrightarrow3^x=9\)
hay x=2
Lời giải:
a)
$3^{2x+1}.7^y=9.21^x=3^2.(3.7)^x=3^{2+x}.7^x$
Vì $x,y$ là số tự nhiên nên suy ra $2x+1=2+x$ và $y=x$
$\Rightarrow x=y=1$
b) \(\frac{27^x}{3^{2x-y}}=\frac{3^{3x}}{3^{2x-y}}=3^{x+y}=243=3^5\Rightarrow x+y=5(1)\)
\(\frac{25^x}{5^{x+y}}=\frac{5^{2x}}{5^{x+y}}=5^{x-y}=125=5^3\Rightarrow x-y=3\) $(2)$
Từ $(1);(2)\Rightarrow x=4; y=1$
3 2 x + 1 + 10 4 x + 2 − 6 6 x + 3 = 12 26 ⇒ 3 2 x + 1 + 10 2 2 x + 1 − 6 3 2 x + 1 = 12 26 ⇒ 3 2 x + 1 + 5 2 x + 1 − 2 2 x + 1 = 12 26 ⇒ 3 + 5 − 2 2 x + 1 = 12 26 ⇒ 6 2 x + 1 = 6 13 ⇒ 2 x + 1 = 13 ⇒ x = 6
`@` `\text {Ans}`
`\downarrow`
`x - 32 \div 16 = 18`
`=> x - 2 = 18`
`=> x = 18 + 2`
`=> x = 20`
Vậy, `x = 20.`
`15 + 2x = 17`
`=> 2x = 17 - 15`
`=> 2x = 2`
`=> x = 2 \div 2`
`=> x = 1`
Vậy, `x = 1`
`324 - 13x = 57*5`
`=> 324 - 13x = 285`
`=> 13x = 324 - 285`
`=> 13x = 39`
`=> x = 39 \div 13`
`=> x = 3`
Vậy, `x = 3.`
`@` `\text {Kaizuu lv uuu}`
a) \(8x+56:14=60\)
\(\Rightarrow8x+4=60\)
\(\Rightarrow8x=56\)
\(\Rightarrow x=\dfrac{56}{8}\)
\(\Rightarrow x=7\)
b) Mình làm rồi nhé !
c) \(41-2^{x+1}=9\)
\(\Rightarrow2^{x+1}=41-9\)
\(\Rightarrow2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
d) \(3^{2x-4}-x^0=8\)
\(\Rightarrow3^{2x-4}-1=8\)
\(\Rightarrow3^{2x-4}=9\)
\(\Rightarrow3^{2x-4}=3^2\)
\(\Rightarrow2x-4=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
g) \(65-4^{x+2}=2014^0\)
\(\Rightarrow65-4^{x+2}=1\)
\(\Rightarrow4^{x+2}=64\)
\(\Rightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
i) \(120+2\left(4x-17\right)=214\)
\(\Rightarrow2\left(4x-17\right)=214-120\)
\(\Rightarrow2\left(4x-17\right)=94\)
\(\Rightarrow4x-17=47\)
\(\Rightarrow4x=47+17\)
\(\Rightarrow4x=64\)
\(\Rightarrow x=16\)
a: \(8x+56:14=60\)
=>8x+4=60
=>8x=60-4=56
=>x=56/8=7
b: \(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
=>\(5^{2x-3}=5^2\cdot3+2\cdot5^2=5^3\)
=>2x-3=3
=>2x=6
=>x=3
c: \(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>x+1=5
=>x=4
d: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}-1=8\)
=>\(3^{2x-4}=8+1=9\)
=>2x-4=2
=>2x=6
=>x=3
g: \(65-4^{x+2}=2014^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
i: 120+2(4x-17)=214
=>2(4x-17)=214-120=94
=>4x-17=94/2=47
=>4x=64
=>\(x=\dfrac{64}{4}=16\)
Từ 1 đến x có (x-1):2+1 số hạng
Số cặp là ((x-1):2+1):2
tổng mỗi cặp là 1+x
Suy ra x=79
32x+1+32x=324
=> 32x.(31+1)=324
=> 32x.4=324
=> 32x=81
=> 32x=34
=> 2x=4
=> x=2