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a) 53( 3x + 2 ) : 13 = 103 : ( 135 : 134 )
=> 53( 3x + 2 ) : 13 = 103 : 13
=> 53( 3x + 2 ) = 103 : 13 : 13
=> 53( 3x + 2 ) = 103
=> 3x + 2 = 23
=> 3x + 2 = 8
=> 3x = 6
=> x = 2
a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot25\right)\div14=5^2-16\)
\(\left(19x+50\right)\div14=25-16=9\)
\(19x+50=9\cdot14=126\)
\(19x=126-50=76\)
\(x=76\div19=4\)
b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)
\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)
\(2\cdot3^x=18\cdot3^{12}\)
\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)
a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15
\(x\in\left(\infty;-\infty\right)\)
\(\frac{19x+50}{14}=\frac{9}{1}\Rightarrow\left(19x+50\right)1=14.9\)
\(\frac{\left(19x+50\right)1}{19x}=\frac{14.9}{19x}\)
\(\frac{19x+50}{19x}=\frac{14.19}{19x}\)
\(\Rightarrow x=4\)
a, \(\left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19.x+2.25\right)\div14=5^2-4^2\)
\(\left(19.x+2.25\right)\div14=25-16\)
\(\left(19.x+50\right)\div14=9\)
\(\left(19.x+50\right)=9.14\)
\(19.x+50=126\)
\(19.x=126-50\)
\(19.x=76\)
\(\Rightarrow x=76\div19\)
\(\Rightarrow x=4\)
Vậy x = 4
b, \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=10.3^{12}+8.3^{12}\)
\(2.3^x=\left(10+8\right).3^{12}\)
\(2.3^x=18.3^{12}\)
\(2.3^x=2.3^3.3^{12}\)
\(2.3^x=2.3^{15}\)
\(\Rightarrow x=15\)
Vậy x = 15
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
a: x=4/27-2/3=4/27-18/27=-14/27
b: =>3/4x-1/4x=1/6+7/3
=>1/2x=1/6+14/6=5/2
hay x=5
c: =>13/10x=7/2+5/2=6
=>x=13/10:6=13/60
d: (3x+2)(-2/5x-7)=0
=>3x+2=0 hoặc 2/5x+7=0
=>x=-2/3 hoặc x=-35/2
4-(27-3) = x- (13-4)
4-24= x - 9
-20 = x-9
x-9 = -20
x = -20+9
x = -11
Vậy : x = -11
8-(x-10) = 23-(-4+12)
8-(x-10) = 23-8
8-(x-10) = 15
x-10 = 8-15
x-10 = -7
x = -7+10
x = 3
Vậy : x = 3
4 – (27 – 3) = x – (13 – 4)
4 – 27 + 3 = x – 13 + 4 (bỏ ngoặc)
4 – 27 + 3 + 13 – 4 = x (chuyển vế –13 và 4)
–27 + 16 = x
–11 = x.
Vậy x = –11.
\(\frac{10}{3}.x-\frac{27}{4}=\frac{13}{4}\)
\(\frac{10}{3}.x=\frac{13}{4}+\frac{27}{4}\)
\(\frac{10}{3}.x=10\)
\(x=10:\frac{10}{3}\)
\(x=3\)