Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Y : 5 + Y : 3 + Y = 69
Y : (5 + 3 + 1) = 69
Y : 9 = 69
Y = 69 . 9
Y = 621
\(y:5+y:3+y=69\)
\(y\times\frac{1}{5}+y\times\frac{1}{3}+y=69\)
\(y\times\left(\frac{1}{5}+\frac{1}{3}+1\right)=69\)
\(y\times\frac{23}{15}=69\)
\(y=69:\frac{23}{15}=69\times\frac{15}{23}=45\)
Vậy y=45
1)\(\frac{252}{x}=\frac{84}{97}\Rightarrow\)\(\frac{84}{97}=\frac{252}{291}\Rightarrow x=291\)
6) \(\frac{y}{15}=\frac{2}{5}\Rightarrow\frac{2}{5}=\frac{6}{15}\Rightarrow x=6\)
mình ko chép đề bài nha
a) \(\dfrac{16}{5}\): \(\dfrac{7}{3}\) : y =\(\dfrac{12}{7}\)
\(\dfrac{48}{35}\): y = \(\dfrac{12}{7}\)
y = \(\dfrac{48}{35}\): \(\dfrac{12}{7}\)
y = \(\dfrac{4}{5}\)
\(a,5\frac{1}{4}+3,25-50\%+y=15,25\)
\(\Leftrightarrow5,25+3,25-\frac{50}{100}+y=15,25\)
\(\Leftrightarrow5,25+3,25-0,5+y=15,25\)
\(\Leftrightarrow8+y=15,25\)
\(\Leftrightarrow y=15,25-8=7,25\)
\(b,(y-3):2=2010\)
\(\Leftrightarrow y-3=4020\)
\(\Leftrightarrow y=4023\)
\(y+y.\frac{1}{3}.\frac{9}{2}+y.\frac{7}{2}=25\)
\(y+y.6+y.\frac{7}{2}=25\)
\(y.\left(1+6+\frac{7}{2}\right)=25\)
\(y.\frac{21}{2}=25\)
\(y=25:\frac{21}{2}\)
\(y=25.\frac{2}{21}\)
\(y=\frac{50}{21}\)
\(y.5+y.3+y+y=50\)
\(y.\left(5+3+1+1\right)=50\)
\(y.10=50\)
\(y=5\)
1/2-2y=9/20
=>2y=1/2-9/20=1/20
=>y=1/20:2=1/40
b,3/5:4/3:y=2+7/10=9/20:y=27/10
=>y=9/20:27/10=1/6
c,y+y*3/2-y*1/2=1/10
=>y(1+3/2-1/2)=1/10
=>2y=1/10
=>y=1/10:2=1/20
y + y x 4,5 : 3 + y x 7 : 2 = 255
y + y x 1,5 + y x 3,5 = 255
3y x (1,5 + 3,5) = 255
3y x 5 = 255
3y = 255 : 5
3y = 51
y = 51 : 3
y = 17
\(\frac{2}{3}:\frac{y}{9}:\frac{7}{5}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\)
\(\frac{2}{3}\cdot\frac{9}{y}\cdot\frac{5}{7}=\frac{2}{7}\cdot\frac{5}{3}\cdot\frac{9}{10}\)
\(\frac{2\cdot9\cdot5}{3\cdot y\cdot7}=\frac{2\cdot5\cdot9}{7\cdot3\cdot10}\)
\(\frac{30}{7\cdot y}=\frac{3}{7}\)
\(\Leftrightarrow30\cdot7=7\cdot y\cdot3\)
210 = 21 * y
y = 10
2/3 : y/9 : 7/5 = 2/7 : 3/5 : 10/9
= 2/3 : y/9 : 7/5 = 3/70
= 2/3 : y/9 = 3/70 x 7/5
= 2/3 : y/9 = 3/50
y/9 = 2/3 : 3/50
y/9 = 100/9
vậy y = 100
