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\(\dfrac{x^2}{6}=\dfrac{24}{25}\)
\(\Leftrightarrow x^2=\dfrac{144}{25}\)
hay \(x\in\left\{\dfrac{12}{5};-\dfrac{12}{5}\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{x^2}{6}=\dfrac{24}{25}\)
\(\Rightarrow x^2=\dfrac{24.6}{25}=\dfrac{144}{25}\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ĐKXĐ: \(x\ne-5\)
\(\Leftrightarrow7x-7=6x+30\\ \Leftrightarrow x=37\)
b) \(\Leftrightarrow25x^2=144\\ \Leftrightarrow x^2=\dfrac{144}{25}\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x^2}{6}=\frac{24}{25}\)
\(x^2\cdot25=6\cdot24\)
\(x^2\cdot25=144\)
\(x^2=144:25\)
\(x=\pm\sqrt{\frac{12}{5}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\frac{x^2}{6}=\frac{24}{25}\Leftrightarrow x^2.25=24.6\)
\(\Leftrightarrow x^2=\frac{24.6}{25}=\frac{144}{25}=5,76\)
\(\Leftrightarrow x=\sqrt{5,76}=2,4;x=-\sqrt{5,76}=-2,4\)
Vậy \(x=2,4\) hoặc \(x=-2,4\)
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\(\frac{x^2}{6}=\frac{24}{25}\)
=> x2 . 25 = 6 . 24
=> x2 . 25 = 144
=> x2 = 5,76
=> x = \(\sqrt{5,76}\) = 2,4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x.x}{6}=\frac{24}{25}\Rightarrow25.x^2=24.6=144\Rightarrow x^2=\frac{144}{25}=\left(\frac{12}{5}\right)^2=\left(-\frac{12}{5}\right)^2\)
=> x =12/5 hoặc x = -12/5
\(x\times\frac{x}{6}=\frac{24}{25}\)
\(x=\frac{24}{25}:\frac{x}{6}\)
\(x=\frac{84}{25x}\)
\(25x^2=84\)
\(x^2=3,36\)
\(x=\frac{2\sqrt{21}}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x-2/5=3/8
(x-2).8=5.3
x-2=5.3:8
x-2=1
=>x=3
b,c )tương tự
\(x^2=\frac{144}{25}=\left(\frac{12}{5}\right)^2\Leftrightarrow\orbr{\begin{cases}x=\frac{12}{5}\\x=-\frac{12}{5}\end{cases}}\)