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3x(12x – 4) – 9x(4x – 3) = 30
3x.12x – 3x.4 – (9x.4x – 9x.3) = 30
36x2 – 12x – 36x2 + 27x = 30
(36x2 – 36x2) + (27x – 12x) = 30
15x = 30
x = 2
Vậy x = 2.
3x (12x -4 )- 9x (4x-3)= 30
<=>36x2-12x-36x3+27x=30
<=>15x=30
<=>x=2
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(36x^2-12x-36x^2+27x=30\)
\(15x=30\)
\(x=\frac{30}{15}\)
\(x=2\)
= 36X-12X-36X-27X=30
=36X-36X-12X-27X=30
=0-12X-27X
=-12X-27X=30
=X.(-12-27)=30
hình như mình tính sai
nếu công thức đúng thì k nha
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Leftrightarrow15x=30\)
\(\Leftrightarrow x=2\)
3x(12x - 4 ) -9x (4x -3 ) = 30
<=> 36x² - 12x - 36x²+27x = 30
<=> 15x = 30
<=> x=2
\(3x\left(12x-4\right)-9.\left(4x-3\right)=30\)
\(=>36x^2-12x-36x^2+27x=30\)
\(=>15x=30\)
\(x=30:15=2\)
Vậy x = 2.
~ Hok tốt ~
`@` `\text {Ans}`
`\downarrow`
`a)`
`3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30`
`=> 3x (12x-4) - 3*3x (4x - 3) = 30`
`=> 3x [12x - 4 - 3(4x-3)] = 30`
`=> 3x (12x - 4 - 12x + 9) = 30`
`=> 3x (-4+9)=30`
`=> 3x*5=30`
`=> 3x=6`
`=> x=2`
Vậy, `x=2`
`b)`
`x( 5 - 2x) + 2x( x - 1)`
`=> x(5-2x) + 2x^2 - 2x=15`
`=> 5x - 2x^2 + 2x^2 - 2x =15`
`=> 3x = 15`
`=> x=5`
Vậy, `x=5.`
a: =>36x^2-12x-36x^2+27x=30
=>15x=30
=>x=2
b: =>5x-2x^2+2x^2-2x=15
=>3x=15
=>x=5
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)
\(\Leftrightarrow27x-12x=30\)
\(\Leftrightarrow15x=30\)
\(\Leftrightarrow x=\frac{30}{15}=2\)
a) \(3x\cdot\left(12x-4\right)-9x\cdot\left(4x-3\right)=30\)
\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)
\(\Leftrightarrow15x=30\)
\(\Leftrightarrow x=\dfrac{30}{15}\)
\(\Leftrightarrow x=2\)
b) \(\left(2x+1\right)-5\left(x-2\right)=10\)
\(\Leftrightarrow2x+1-5x+10=10\)
\(\Leftrightarrow-3x+11=10\)
\(\Leftrightarrow-3x=10-11\)
\(\Leftrightarrow-3x=-1\)
\(\Leftrightarrow x=\dfrac{1}{3}\)
Ta có
3x(12x-3)-9x(4x-4)=120
<=> 36x2-9x-36x2+36x=120
<=> 27x=120
=> x=40/9