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LK
1
6 tháng 9 2021
\(\frac{2x-10}{6}=\frac{-27}{5-x}\)
\(\frac{2\left(x-5\right)}{6}=\frac{27}{x-5}\)
\(2\left(x-5\right)^2=27\times6\)
\(2x^2-20x+50-162=0\)
\(2x^2-20x-112=0\)
\(x^2-10x-56=0\)
\(x^2-14x+4x-56=0\)
\(\left(x-14\right)\left(x+4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-14=0\\x+4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)
KL .....
XIN TIICK
AV
1
XO
11 tháng 8 2019
\(\frac{10-2x}{6}=\frac{27}{5-x}\)
\(\Rightarrow\frac{2.\left(5-x\right)}{6}=\frac{27}{5-x}\)
\(\Rightarrow\frac{5-x}{3}=\frac{27}{5-x}\)
\(\Rightarrow\left(5-x\right).\left(5-x\right)=3.27\)
\(\Rightarrow\left(5-x\right)^2=81\)
\(\Rightarrow\left(5-x\right)^2=9^2\)
\(\Rightarrow5-x=\pm9\)
\(\Rightarrow\orbr{\begin{cases}5-x=9\\5-x=-9\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-4\\x=14\end{cases}}\)
6 tháng 10 2020
=> (10 - 2x)(5 - x) = 27.6
=> 10(5 - x) - 2x(5 - x) = 162
=> 50 - 10x - 10x + 2x2 = 162
=> 50 - 20x + 2x2 = 162
=> 2(x2 - 10x +25) = 162
=> x2 - 10x + 25 = 81
=> x2 - 2.x.5 + 52 = 81
=> (x - 5)2 = 81
=> (x - 5)2 = (\(\pm\)9)2
+) x + 5 = 9 => x = 4
+) x + 5 = -9 => x = -14
6 tháng 10 2020
Tìm x
\(\frac{10-2x}{6}=\frac{27}{5-x}\Leftrightarrow\left(10-2x\right)\left(5-x\right)=6.27\)
\(\Leftrightarrow10\left(5-x\right)-2x\left(5-x\right)=162\)
\(\Leftrightarrow50-10x-10x+2x^2=162\)
\(\Leftrightarrow50-20x+2x^2=126\)
\(\Leftrightarrow2\left(x^2-10x+25\right)=162\)
\(\Leftrightarrow\left(x-5\right)^2=162:2\)
\(\Leftrightarrow\left(x-5\right)^2=81\)
\(\Leftrightarrow\hept{\begin{cases}x-5=9\\x-5=-9\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=4\\x=-14\end{cases}}\)
M
4
1 tháng 10 2020
a, \(\frac{\left(5-2x\right)}{3}=\frac{\left(4x-1\right)}{-5}\)
\(\Leftrightarrow-5(5-2x)=3\left(4x-1\right)\)
\(\Leftrightarrow10x-25=12x-3\)
\(\Leftrightarrow10x-12x=25-3\)
\(\Leftrightarrow-2x=22\)
\(\Leftrightarrow x=-11\)
b, \(\frac{\left(12-3x\right)}{32}=\frac{6}{\left(4-x\right)}\)
\(\Leftrightarrow\frac{3\left(4-x\right)}{32}=\frac{6}{\left(4-x\right)}\)
\(\Leftrightarrow3(4-x)\left(4-x\right)=32.6\)
\(\Leftrightarrow(4-x)\left(4-x\right)=32.2\)
\(\Leftrightarrow(4-x)^2=64\)
\(\Leftrightarrow\orbr{\begin{cases}4-x=8\\4-x=-8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=12\end{cases}}\)
c, \(\frac{\left(10-2x\right)}{6}=\frac{27}{\left(5-x\right)}\)
\(\Leftrightarrow\frac{2\left(5-x\right)}{6}=\frac{27}{\left(5-x\right)}\)
\(\Leftrightarrow2(5-x)\left(5-x\right)=27.6\)
\(\Leftrightarrow(5-x)\left(5-x\right)=27.3\)
\(\Leftrightarrow(5-x)^2=81\)
\(\Leftrightarrow\orbr{\begin{cases}5-x=9\\5-x=-9\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=14\end{cases}}\)
A
1 tháng 10 2020
a, \(\frac{5-2x}{3}=\frac{4x-1}{-5}\Leftrightarrow-25+10x=12x-3\Leftrightarrow-22-2x=0\Leftrightarrow x=-11\)
b, \(\frac{12-3x}{32}=\frac{6}{4-x}\Leftrightarrow\frac{12-3x}{32}=\frac{18}{12-3x}\)
\(\Leftrightarrow\left(12-3x\right)^2=576\Leftrightarrow12-3x=\pm2\)\(\Leftrightarrow\orbr{\begin{cases}x=\frac{10}{3}\\x=\frac{14}{3}\end{cases}}\)
c, \(\frac{10-2x}{6}=\frac{27}{5-x}\Leftrightarrow\frac{10-2x}{6}=\frac{54}{10-2x}\)
\(\Leftrightarrow\left(10-2x\right)^2=324\Leftrightarrow10-2x=\pm18\)\(\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)
1 tháng 8 2018
a) \(5-\frac{2x}{3}=4x-\frac{1}{-5}\)
\(\frac{75-10x}{15}=\frac{60x+3}{15}\)
75 - 10x = 60x +3
72 = 70x
\(\frac{72}{70}\) = x
x =\(\frac{36}{35}\)
Vậy x = \(\frac{36}{35}\)
b) \(2x-\frac{10}{6}=\frac{-27}{5}-x\)
\(2x-\frac{5}{3}=\frac{-27}{5}-x\)
\(\frac{30x-25}{15}=\frac{-81-15}{15}\)
30x =-96+25
30x =-71
x= -71/30
Vậy x= -71/30
c) \(13x-\frac{2}{2x}+5=\frac{76}{17}\)
13x - 1/x +5 = 76/17
\(\frac{221x-17+85}{17x}=\frac{76x}{17x}\)
221x +68 = 76x
221x-76x =-68
145x =-68
x =\(\frac{-68}{145}\)
Vậy .........
17 tháng 4 2020
\(10-\frac{2x}{6}=\frac{27}{5}-x\)
\(-\frac{2x}{6}+x=\frac{27}{5}-10\)
\(-\frac{2x}{6}+\frac{6x}{6}=-\frac{23}{5}\)
\(\frac{2}{3}x=\frac{-23}{5}\)
\(x=\frac{-23}{5}:\frac{2}{3}\)
\(x=\frac{-69}{10}\)
học tốt
SS
25 tháng 6 2019
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8-6^8.20}\)
\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8-\left(2.3\right)^8.2^2.5}\)
\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8-2^{10}.3^8.5}\)
\(A=\frac{2^{10}.\left(3^8-3^9\right)}{2^{10}.3^8.\left(1-5\right)}=\frac{3^8-3^9}{3^8.\left(-4\right)}=\frac{3^8.\left(1-3\right)}{3^8.\left(-4\right)}=\frac{-2}{-4}=\frac{1}{2}\)
Vậy A = \(\frac{1}{2}\)
\(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(B=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)
\(B=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(B=\frac{2^{19}.3^9+3^9.2^{18}.5}{2^{19}.3^9+2^{20}.3^{10}}\)
\(B=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9\left(1+2.3\right)}=\frac{7}{2.7}=\frac{1}{2}\)
Vậy B = \(\frac{1}{2}\)
23 tháng 9 2019
a)\(\frac{x}{4}=\frac{9}{10}\)
\(\Rightarrow x.10=4.9\)
\(\Rightarrow x.10=36\)
.....
b)\(\frac{x}{24}=\frac{6}{x}\)
\(\Rightarrow x^2=6.24\)
\(\Rightarrow x^2=144\)
\(\Rightarrow x=12\)
TT
24 tháng 12 2017
a,\(\dfrac{2}{3}x-\dfrac{4}{9}=-\dfrac{5}{27}\)
\(\dfrac{2}{3}x=\dfrac{17}{27}\)
\(x=\dfrac{17}{18}\)
b,\(\dfrac{2}{3}x+\dfrac{4}{9}=\dfrac{5}{27}\)
\(\dfrac{2}{3}x=-\dfrac{7}{27}\)
\(x=-\dfrac{7}{18}\)
c,\(x:1,2=5,4:6\)
\(x:1,2=0,9\)
\(x=1,08\)
d,\(1,68:1,2=5,4:x\)
\(1,4=5,4:x\)
\(x=\dfrac{27}{7}\)
e,\(\left(1-2x\right)^2+1=10\)
\(\left(1-2x\right)^2=9\)
\(1-2x=3\)
\(2x=-2\)
\(x=-1\)
f,\(\left(1-2x\right)^2-6=10\)
\(\left(1-2x\right)^2=16\)
\(1-2x=4\)
\(2x=-3\)
\(x=-\dfrac{3}{2}\)