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`#3107.101107`
`a)`
Ta có:
\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)
Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)
\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)
`b)`
Ta có:
\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)
\(\dfrac{111}{311}=1-\dfrac{200}{311}\)
Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)
\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)
\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)
Ta có: \(\frac{22}{33}=\frac{2}{3}=\frac{12}{18}>\frac{12}{19}\)
Vậy \(\frac{12}{19}< \frac{22}{33}\)
39/12>116/40
37/90>35/111
23/28<24/27
nha Nguyễn Thùy Linh
\(a,\dfrac{2727}{3131}=\dfrac{2727:101}{3131:101}=\dfrac{27}{31}\\ Vậy:\dfrac{27}{31}=\dfrac{2727}{3131}\)
A = 2010 × 2011 - 1945 / 2010 × 2010 + 65
A = 2010 × 2010 + ( 2010 - 1945) / 2010 × 2010 + 65
A = 2010 × 2010 + 65 / 2010 × 2010 + 65
A = 1
B = 2001 × 2001 + 111 / 2001 × 2002 - 1890
B = 2001 × 2001 + 111 / 2001 × 2001 + ( 2001 - 1890)
B = 2001 × 2001 + 111 / 2001 × 2001 + 111
B = 1
=> A = B
a) \(\frac{25}{26}=\frac{50}{52}\) b) \(\frac{51}{58}< \frac{61}{68}\) c) \(\frac{101}{506}< \frac{707}{3534}\)
So sánh \(\dfrac{33}{68}\) và \(\dfrac{56}{111}\)
\(\dfrac{33}{68}\) < \(\dfrac{33}{66}\) = \(\dfrac{33:33}{66:33}\) = \(\dfrac{1}{2}\)
\(\dfrac{56}{111}\) > \(\dfrac{56}{112}\) = \(\dfrac{56:56}{112:56}\) = \(\dfrac{1}{2}\)
\(\dfrac{33}{68}\) < \(\dfrac{1}{2}\) < \(\dfrac{56}{111}\)
Vậy \(\dfrac{33}{68}\) < \(\dfrac{56}{111}\)
33/68<33/66
33/66=33:33/66:33= 1/2
56/111> 5/112=56:56/112:56=1/2
33/68<1/2<5/112 nên 56/111>33/68
Tk ạ