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a. \(\dfrac{1}{5}\) đã tối giản
\(\dfrac{4}{120}=\dfrac{1}{30}\)
\(\dfrac{-50}{60}=\dfrac{-5}{6}\)
Quy đồng: \(BCNN\left(5,30,6\right)=30\)
\(\Rightarrow\dfrac{1}{5}=\dfrac{1.6}{5.6}=\dfrac{6}{30};\dfrac{1}{30}=\dfrac{1.1}{30.1}=\dfrac{1}{30};\dfrac{-5}{6}=\dfrac{-5.5}{6.5}=\dfrac{-25}{30}\)
b. \(\dfrac{-25}{30}< \dfrac{1}{30}< \dfrac{6}{30}\)
a,\(\dfrac{4}{120}=\dfrac{1}{30};\dfrac{-50}{60}=\dfrac{-5}{6}\)
\(\dfrac{1}{5}=\dfrac{1.6}{5.6}=\dfrac{6}{30};\dfrac{1}{30};\dfrac{-5}{6}=\dfrac{-5.5}{6.5}=\dfrac{-25}{30}\)
b, Vì \(\dfrac{6}{30}>\dfrac{1}{30}>\dfrac{-25}{30}\) nên => \(\dfrac{4}{120}>\dfrac{1}{30}>\dfrac{-50}{60}\)
Câu 3:
a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)
\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)
b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)
\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)
Câu 4:
a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)
b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)
\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)
\(=-27\cdot100-23\cdot100\)
\(=100\left(-27-23\right)\)
\(=-50\cdot100=-5000\)
c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)
d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)
\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)
\(=-1+1+\dfrac{5}{6}\)
\(=\dfrac{5}{6}\)
\(\dfrac{-8}{12}=\dfrac{-8:4}{12:4}=\dfrac{-2}{3}\\ \dfrac{15}{-60}=\dfrac{15:15}{-60:15}=\dfrac{1}{-4}\\ \dfrac{-16}{-72}=\dfrac{-16:\left(-8\right)}{-72:\left(-8\right)}=\dfrac{2}{9}\\ \dfrac{35}{14.15}=\dfrac{5.7}{7.2.5.3}=\dfrac{1}{2.3}=\dfrac{1}{6}\)
\(\dfrac{14}{21}=\dfrac{7\cdot2}{7\cdot3}=\dfrac{2}{3}\)
\(\dfrac{-36}{48}=\dfrac{-12\cdot3}{12\cdot4}=-\dfrac{3}{4}\)
\(\dfrac{28}{-52}=\dfrac{7\cdot4}{-4\cdot13}=-\dfrac{7}{13}\)
\(\dfrac{-54}{-90}=\dfrac{-18\cdot3}{-18\cdot5}=\dfrac{3}{5}\)
\(\dfrac{14}{21}\) =\(\dfrac{2}{3}\)
\(\dfrac{-36}{48}\) =\(\dfrac{3}{4}\)
\(\dfrac{28}{-52}\)=\(\dfrac{7}{-13}\)
\(\dfrac{-54}{-90}\) =\(\dfrac{6}{9}=\dfrac{2}{3}\)
\(\dfrac{-12}{-4}=\dfrac{-3}{-1}\)
\(\dfrac{7}{-35}=\dfrac{1}{-5}\)
\(\dfrac{-9}{27}=\dfrac{-1}{3}\)
Rút gọn các phân số sau:
\(\dfrac{{ - 12}}{{ - 4}}\);\(\dfrac{7}{{ - 35}}\); \(\dfrac{{ - 9}}{{27}}\)
\(\dfrac{{ - 12}}{{ - 4}} = \dfrac{{ - 12:\left( { - 4} \right)}}{{\left( { - 4} \right):\left( { - 4} \right)}} = 3\)
\(\dfrac{7}{{ - 35}} = \dfrac{{7:\left( { - 7} \right)}}{{ - 35:\left( { - 7} \right)}} = \dfrac{{ - 1}}{5}\)
\(\dfrac{{ - 9}}{{27}} = \dfrac{{ - 9:9}}{{27:9}} = \dfrac{{ - 1}}{3}\)
a: \(=\dfrac{-4\cdot13\cdot9\cdot5}{3\cdot4\cdot5\cdot2\cdot13}=\dfrac{3}{2}\)
b: \(=\dfrac{1}{2}\cdot\dfrac{1}{3}\cdot5=\dfrac{5}{6}\)
(2⁵⁰.5³⁵)/(2⁵¹.5³⁶)
= (2⁵⁰/2⁵¹).(5³⁵/5³⁶)
= 1/2 . 1/5
= 1/10
\(\dfrac{2^{50}\cdot5^{35}}{2^{51}\cdot5^{36}}\)
\(=\dfrac{2^{50}\cdot5^{35}}{2\cdot2^{50}\cdot5^{35}\cdot5}\)
\(=\dfrac{1}{2\cdot5}\)
\(=\dfrac{1}{10}\)