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\(\frac{16\times8-16\times2}{12+4}\)
\(=\frac{16\times\left(8-2\right)}{16}\)
\(=\frac{16\times6}{16}\)
\(=6\)
\(=\frac{16\left(8+2\right)}{16}\)
\(=\frac{16.10}{16}\)
\(=10\)

\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)\div x=\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{32}\right)\)
\(\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)\div x=\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{11.12}\right)\)
\(\frac{15}{16}\div x=\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{12}\right)\)
\(\frac{15}{16}\div x=\left(\frac{1}{1}-\frac{1}{12}\right)\)
\(\frac{15}{16}\div x=\frac{11}{12}\)
\(x=\frac{15}{16}\div\frac{11}{12}\)
\(x=\frac{15}{16}\times\frac{12}{11}\)
\(\Rightarrow x=\frac{180}{176}=\frac{45}{44}\)

+ \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\)
=> \(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\)
=> \(A=2A-A=1-\frac{1}{16}=\frac{15}{16}\)
+ \(B=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{11x12}\)
\(B=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+...+\frac{12-11}{11x12}\)
\(B=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\)
\(B=1-\frac{1}{12}=\frac{11}{12}\)
\(A:x=B\Rightarrow x=A:B=\frac{15}{16}:\frac{11}{12}=\frac{15}{16}x\frac{12}{11}=\frac{45}{44}=1\frac{1}{44}\)
Gửi câu trả lời của bạn

1.
( 10 - 9,34 ) + ( 10 - 9,66 )
= 0,66 + 0,34
= 1
12 - ( 12 - 9,36 )
= 12 - 2,64
= 9,36
38,52 + 0,302 x 100 - 0,72
= 38,52 + 30,2 - 0,72
= 68,72 - 0,72
= 68
2.
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0+1=1\)
\(\left(x-\frac{151}{12}\right):\frac{50}{3}=1\)
\(x-\frac{151}{12}=1\times\frac{50}{3}\)
\(x-\frac{151}{12}=\frac{50}{3}\)
\(x=\frac{50}{3}+\frac{151}{12}\)
\(x=\frac{117}{4}\)
Bài 1
\(\left(10-9,34\right)+\left(10-9,66\right)\)
\(=0.66+0,34=1\)
\(12-\left(12-9,36\right)\)
\(=12-2.64=9,36\)
\(38,52+0,302.100-0,72\)
\(=38,52+30,2-0,72\)
\(=7.6\)
Bài 2
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\frac{43}{8}+x-\frac{173}{24}=\frac{3}{50}\)
\(\frac{43}{8}+x=\frac{3}{50}+\frac{173}{24}\)
\(\frac{43}{8}+x=\frac{4361}{600}\)
\(x=\frac{142}{75}\)( gửi lại bài 2 đã )

A, ( X + 1,5 ) + ( X + 3 ) + ( X + 4.5 ) + ......+ ( X + 12 )
= 8X + ( 1,5 + 3 + 4,5 + ....+ 12)
= 8X + 54 = 156
8X = 156
X = 19,5
B, 24,3 + X : 16 - 3,4 = 30,34
24,3 + X : 16 = 30,34 + 3,4 = 33,74
X : 16 = 33,74 - 24,3 = 9,44
X = 9,44 x 16 = 151,04
C, ( X + 5,2 ) : 3,2 = 4,7 ( dư 0,5)
X + 5,2 = 4,7 x 3,2 + 0,5 = 15,54
X = 15,54 - 5,2
X = 10,34
A)
(x + 1,5) + (x + 3 ) + (x + 4,5) + .......... + (x + 12 ) = 156
=> x + 1,5 + x + 3 + x + 4,5 + ..........+ x + 12 = 156
=> (x + x + x + x + x + x + x + x) + ( 1,5 + 3 + 4,5 + 6 + 7,5 + 9 + 10,5 + 12 ) = 156
=> 8 \(\times\) x + (1,5 + 12 ) \(\times\) ( 8 : 2 ) = 156
=> 8\(\times\)x + 13,5 \(\times\) 4 = 156
=> 8\(\times\)x + 54 = 156
=> 8 \(\times\) x = 102
=> x = 102 : 8
=> x = 12,75
B) 24,3 + x : 16 - 3,4 = 30,34
=> 24,3 + x : 16 = 33,74
=> x : 16 = 9,44
=> x = 9,44 \(\times\) 16
=> x = 151,04
C) ( x + 5,2 ) : 3,2 = 4,7 (du 0,5 )
=> ( x + 5,2) \(\times\)4,7= 3,2 + 0,5
=> (x + 5,2 ) \(\times\)4,7 = 3,7
=> x + 5,2 = 3,7 : 4,7
=> x + 5,2 = \(\frac{37}{47}\)
=> x = \(\frac{37}{47}-5,2\)
=> x = \(-\frac{1037}{235}\)

a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)

mình xin nhầm đề là: A = \(1*2*3+2*4*6+4*8*12+8*16*24 \over2*3*4+4*6*8+8*12*16+16*24*32\)
Áp dụng BĐT phụ [tex](a+b)^{2}\geq 4ab[/tex] và [tex]\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\geq \frac{9}{a+b+c}[/tex] với a,b,c dương ta được
$P\geq \frac{2.4ab}{2x+3y}+\frac{4y.2z}{2y+z}+\frac{4.2z.x}{z+2x}$
$=8.(\frac{xy}{2x+3y}+\frac{yz}{2y+z}+\frac{zx}{z+2x})$
$= 8.(\frac{1}{\frac{2}{y}+\frac{3}{x}}+\frac{1}{\frac{2}{z}+\frac{1}{y}}+\frac{1}{\frac{1}{x}+\frac{2}{z}})$
$\geq 8.\frac{9}{\frac{2}{y}+\frac{3}{x}+\frac{2}{z}+\frac{1}{y}+\frac{1}{x}+\frac{2}{z}}$
$=\frac{72}{\frac{3}{y}+\frac{4}{x}+\frac{4}{z}}$
$=\frac{72}{\frac{4yz+4yz+3xz}{xyz}}$
$=\frac{72}{\frac{3xyz}{xyz}}=24$
156: (8 + 16 + x/x (là sao em)