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\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(=\left(x-y\right)^2-2\left(x-y\right)=\left(x-y\right)\left(x-y-2\right)\)
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
\(4x^2-4y^2-4y-1\)
\(\Leftrightarrow4x^2-\left(2y+1\right)^2\)
\(\Leftrightarrow\left(2x-2y-1\right)\left(2x+2y+1\right)\)
P/s tham khảo nha
\(=4x^2-\left(4y^2+4y+1\right)\)
\(=4x^2-\left(4y^2+4y+1^2\right)\)
\(=\left(2x\right)^2-\left(2y+1\right)^2\)
\(=\left(2x-2y-1\right)\left(2x+2y+1\right)\)
\(=3^2-\left(x-y\right)^2=\left[3-\left(x-y\right)\right]\left[3+\left(x-y\right)\right]=\left(3-x+y\right)\left(3+x-y\right)\)
\(9-x^2+2xy-y^2\)
\(=9-\left(x^2-2xy+y^2\right)\)
\(=3^2-\left(x-y\right)^2\)
\(=\left(3-x+y\right)\left(3-x-y\right)\)
\(x^2+4xy+4y^2=x^2+2x.2y+\left(2y\right)^2=\left(x+2y\right)^2\)
\(x^2-2xy+y^2-36=\left(x-y\right)^2-6^2=\left(x-y+6\right)\left(x-y-6\right)\)