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1. 25 : 5,7 = 250/57
2. 30:2.8.4 = 480
3. 20:2^2.14= 70
4. 125:5^3.170= 170
5. 64:2^5.30.4=240
6. (25:5^2.30): 15.7=14
bạn à! Nhiều quá mình ko làm hết được. sorry nha.^-^

Ta có:
\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)

a) \(\frac{8}{2^3.25}=\frac{8}{8.25}=\frac{1}{25}\)
\(\frac{10}{2^2.5^2.7}=\frac{100}{10^2.7}=\frac{1}{70}\)
Mẫu chung của 2 phân số là 350

a, ( 19.x + 2.52 ) : 14 = ( 13 - 8 )2
=> ( 19.x + 6,25 ) : 14 = 25
=> ( 19.x + 6,25 ) = 25 . 14
=> ( 19.x + 6,25 ) = 350
=> 19.x = 350 - 6,25
=> 19.x = 343,75
=> x = 343,75 : 19
=> x = ?
a) (19x + 50) : 14 = 9 nên x=4
b) 2.3x = 10.312 + 8.312
2.3x = 312 (10 + 8) ; 2.3x = 312.18
3x = 312.32 ; 3x = 314 . Vậy x = 14

a, 7\(x\) - \(x\) = 521 : 519 + 3.22.7
6\(x\) = 53 + 3.4.7
6\(x\) = 125 + 12.7
6\(x\) = 125 + 84
6\(x\) = 209
\(x\) = 209 : 6
\(x\) = \(\dfrac{209}{6}\)
b; 11\(x\) - 7\(x\) + 34 : 33 = 54 + 2\(x\)
4\(x\) + 3 = 625 + 2\(x\)
4\(x\) - 2\(x\) = 625 - 3
2\(x\) = 622
\(x\) = 622 : 2
\(x\) = 311
c; 75 - 5.(\(x-3\))3 = 700
5.(\(x\) - 3)3 = 700 - 75
5.(\(x\) - 3)3 = - 625
(\(x\) - 30)3 = - 625 : 5
(\(x\) - 30)3 = - 125
(\(x-3\))3 = (-5)3
\(x\) - 3 = - 5
\(x\) = - 5 + 3
\(x\) = -2
d, 3.(2\(x\) - 1)2 = 75
(2\(x\) - 1)2 = 75 : 3
(2\(x\) - 1)2 = 25
\(\left[{}\begin{matrix}2x-1=-5\\2x-1=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-5+1\\2x=5+1\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-4\\2x=6\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)

\(3^2x-4-x^0=8\)
9x-4-1=8
9x-5=8
9x=13
=>x=\(\frac{13}{9}\)

ko
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A.\(\frac{2^3.9^2}{2^2.3^2.5}=\frac{2^2.2.\left(3^2\right)^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
B.\(\frac{2^4.5^5.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^3.5^2.11.11.7}{2^3.5^3.7.7.11}=\frac{2.5^2.11}{7}=\frac{61}{7}\)
Đặt Tổng trên là A
\(2A=\frac{8}{1.9}+\frac{16}{9.25}+\frac{24}{25.49}+...+\frac{80}{361.441}\)
\(2A=\frac{9-1}{1.9}+\frac{25-9}{9.25}+\frac{49-25}{25.49}+...+\frac{441-361}{361.441}\)
\(2A=1-\frac{1}{9}+\frac{1}{9}-\frac{1}{25}+\frac{1}{25}-\frac{1}{49}+...+\frac{1}{361}-\frac{1}{441}=1-\frac{1}{441}=\frac{440}{441}\)
\(\Rightarrow A=\frac{220}{441}\)