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Lời giải:
$A=2+4+6+8+...+256$
$=2(1+2+3+4+...+128)$
$=2.128(128+1):2=128.129=16512$
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 2x . 4 = 128
2x = 128 : 4
2x = 32
x = 32 : 2
x = 16
b)x . 17 = x
=> x = 0
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1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)
b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)
c) \(10^8\div10^3=10^{8-3}=10^5\)
d) \(a^7\div a^2=a^{7-2}=a^5\)
2.
\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)
\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)
\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
25 = 32 238 = 78310985281
88 = 16777216 999 = 9135.........899
37 = 2187 476 = 10779215329
67 = 279936 255 = 9765625
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\(a^2\times a^4\times a^6\times......\times a^{50}\)
\(=a^{2+4+6+.....+50}\)
\(=a^{......}\)
Lời giải:
$A=2+4+6+8+...+256$
$=2(1+2+3+...+128)$
$=2.128(128+1):2=128.129=16512=16512^1$