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1 tháng 4 2017

\(A=\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+\dfrac{1}{45}+...+\dfrac{1}{210}\)

\(2.\left(\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}+...+\dfrac{1}{420}\right)\)

\(2.\left(\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}+...+\dfrac{1}{20.21}\right)\)

\(2.\left(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+...\dfrac{1}{20}+\dfrac{1}{21}\right)\)

\(=2.\left(\dfrac{1}{6}-\dfrac{1}{21}\right)=\dfrac{5}{21}\)

1 tháng 4 2017

A = \(\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+\dfrac{1}{45}+...+\dfrac{1}{210}\)

A = \(\dfrac{2}{42}+\dfrac{2}{56}+\dfrac{2}{72}+\dfrac{2}{90}+...+\dfrac{2}{210}\)

A = \(\dfrac{2}{6.7}+\dfrac{2}{7.8}+\dfrac{2}{8.9}+\dfrac{2}{9.10}+...+\dfrac{2}{14.15}\)

A = \(2.\left(\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}+...+\dfrac{1}{14.15}\right)\)

A = \(2.\left(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+...+\dfrac{1}{14}-\dfrac{1}{15}\right)\)

A = \(2.\left(\dfrac{1}{6}-\dfrac{1}{15}\right)\)

A = \(2.\dfrac{1}{10}\)

A = \(\dfrac{2}{10}\)

A = \(\dfrac{1}{5}\)

1 tháng 4 2017

1/2 . A=1/42+1/56+1/72+1/90+...+1/420

1/2 . A=1/6.7+1/7.8+1/8.9+1/9.10+...+1/20.21

1/2 .A=1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+....+1/20-1/21

1/2 . A=1/6-1/21

1/2 .A=5/42

A=5/42:1/2

A=5/21

Chúc bạn học giỏi nhớ tick cho mình nhé

10 tháng 4 2017

oaoa

26 tháng 4 2017

Ta có:

\(A=\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+...+\dfrac{1}{210}\)

=> \(\dfrac{1}{2}A=\dfrac{1}{2}\left(\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+...+\dfrac{1}{210}\right)\text{​}\)

\(=\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+...+\dfrac{1}{420}\)

\(=\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+...+\dfrac{1}{20.21}\)

\(=\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+...+\dfrac{1}{20}-\dfrac{1}{21}\)

\(=\dfrac{1}{6}-\dfrac{1}{21}\)

\(=\dfrac{5}{42}\)

Vậy \(A=\dfrac{5}{42}\)

4 tháng 5 2017

yeu

F= 1/21+1/28+1/36+1/45+...+1/66

F/2=1/42+1/56+1/72+1/90+...+1/132

F/2=1/6.7+1/7.8+1/8.9+1/9.10+...+1/11.12

F/2=1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+...+1/11-1/12

F/2=1/6-1/12

F/2=1/12

F=1/12.2

F=1/6

12 tháng 9 2015

Coi \(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}\)

\(\Rightarrow\frac{1}{2}A=\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}\right).\frac{1}{2}\)

\(=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)

\(=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{2}-\frac{1}{10}=\frac{2}{5}\)

\(\Rightarrow A=\frac{2}{5}:\frac{1}{2}=\frac{4}{5}\)

12 tháng 9 2015

Trần Thùy Dung: hay cho l.i.k.e

15 tháng 4 2018

7/15 nhé bạn!

15 tháng 4 2018

đặt A=1/6+1/10+1/15+1/21+1/28+1/36+1/45

A*2=(1/6*+1/10+1/15+1/21+1/28+1/36+1/45)*2

A*2=1/12+1/20+1/30+1/42+1/56+1/72+1/90

A*2=1/3*4+1/4*5+1/5*6+1/6*7+1/7*8+1/8*9+1/9*10

A*2=1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-/8+1/8-1/9+1/9-1/10

A*2=1/3-1/10

A*2=7/30

A=7/30 / 2

A=7/15

15 tháng 4 2018

\(\frac{4}{5}\)

15 tháng 4 2018

đặt A=1/6+1/10+1/15+1/21+1/28+1/36+1/45

6A=1+3/5+2/5+2/7+3/14+1/6+2/15

6A=1+1+7/14+1/6+2/15

6A=14/5

A=14/5:6=7/15

21 tháng 2 2018

Kết quả là: 9/5 bn nhé!

Chúc bn học tốt!

21 tháng 2 2018

1+1/3+1/6+1/10+1/15+1/21+1/28+1/38+1/45=9/5

5 tháng 9 2021

\(P=\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+\dfrac{1}{45}\)

\(=2\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)\)

\(=2\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\right)\)

\(=2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)

\(=2\left(\dfrac{1}{2}-\dfrac{1}{10}\right)=2.\dfrac{2}{5}=\dfrac{4}{5}\)

5 tháng 9 2021

bn cộng hết lại vs nhau là ra kq!