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a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)
\(\Leftrightarrow\left(x:3+17\right):10+48=50\)
\(\Leftrightarrow\left(x:3+17\right):10=2\)
\(\Leftrightarrow x:3+17=20\)
\(\Leftrightarrow x:3=3\)
hay x=9
b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Leftrightarrow119-\left(x-6\right)=102\)
\(\Leftrightarrow x-6=17\)
hay x=23
c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)
\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)
\(\Leftrightarrow\left(35:x+3\right)=8\)
\(\Leftrightarrow35:x=5\)
hay x=7
\(a,2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(\Rightarrow x=23\)
\(b,2016-100\times\left(x+11\right)=128:8\)
\(2016-100\times\left(x+11\right)=16\)
\(100\times\left(x+11\right)=2016-16\)
\(100\times\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(\Rightarrow x=9\)
\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
Câu 1 :
a) 7x-8=713
7x=713+8
7x=721
x=721:7
x=103
Vậy x=103.
b)2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
Vậy x=23.
c) 2016-100(x+11)=27:23
2016-100(x+11)=24=16
100(x+11)=2016-16
100(x+11)=2000
x+11=2000:100
x+11=20
x=20-11
x=9
Vậy x=9.
Câu 2 :
879.2+879.996+3.879=879(2+996+3)
=879.1001
=879879
2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)
3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)
4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)
5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)
6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)
bài 2
a) 2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
a) (x+12)-20=0
x+12=20
x=8
b) 5.(x-7)=0
x-7=0
x=7
c) 12x-3x+1=937
12x-3x=936
9x=936
x=104
d) 2448 : [ 119 - ( x - 6 ) ] = 24
119-(x-6) = 102
x-6=17
x=23
a ) ( x + 12 ) - 20 = 0
x + 12 = 0 + 20
x +12 = 20
x = 20 - 12
x = 8
b ) 5 . ( x - 7 ) =0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
27.49+27.52-27
=27.(52+49)-27
=27.100-27
=2700-27
=2773
2448:[119-(23-6)]
=2448:[119-17]
=2448:102
=24
(2736-75)-2736
=2736-75-2736
=2736-2736-57
=0-75
=-75
k nhé mk nhanh nhất
A) 7 . x - 8 = 713
7. x = 713 + 8
7 . x = 721
x = 721 : 7
x = 103
A) 7.x-8=713
7.x=713+8
7.x=721
x=721:7
x=103
B) 2448:[119-(x-6)]=24
[119-(x-6)]=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
C) 29016-100.(x+11)=2^7:2^3
29016-100.(x+11)=2^7-3
29016-100.(x+11)=2^4
29016-100.(x+11)=16
100.(x+11)=29016-16
100.(x+11)=29000
x+11=29000:100
x+11=290
x=290-11
x=279
k mik nha