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a). 5x = 125
=>5x = 53
=> x = 3
b) 32x = 81
=> 32x = 34
=> 2x = 4
=> x = 2
c). 52x-3 – 2.52 = 52 .3
=>52x: 53 = 52 .3 + 2.52
=>52x: 53 = 52 .5
=>52x = 52 .5.53
=>52x = 56
=> 2x = 6
=> x=3
a) 5x = 125
x = 125 : 5
x = 25
b) 32x = 81
x = 81 : 32
x = 81/ 32
c) 52x - 3 - 2.52 = 52.3
52x - 3 - 104 = 156
x - 3 - 104 = 156 : 52
x - 3 - 104 = 3
x - 3 = 3 + 104
x - 3 = 107
x = 107 + 3
x = 110
Ko chắc lắm , sai thì Sorry nhé .
a,\(\frac{37.13-13}{24+37.12}=\frac{36.13}{39.12}=1\)
b,125.7.16.25.4=(125.16).(25.4).7=2000.100.7=1400000
c,8.9.14+6.17.12+19.4.18=2^3.3^2.2.7+2.3.17.2^2.3+19.2^2.3^2.2=2^3.3^2.(2.7+17+19)=72.50=3600
\(a,A=\frac{3}{2}+\frac{3}{6}+\frac{3}{12}+\frac{3}{20}+...+\frac{3}{90}\)
\(A=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)
\(A=3.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(A=3.\left(1-\frac{1}{10}\right)\)
\(A=3.\frac{9}{10}=\frac{27}{10}\)
\(b,B=\frac{2}{2.5}+\frac{2}{5.8}+\frac{2}{8.11}+\frac{2}{11.14}+\frac{2}{14.17}\)
\(B.\frac{3}{2}=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}\)
\(B.\frac{3}{2}=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}\)
\(B.\frac{3}{2}=\frac{1}{2}-\frac{1}{17}\)
\(B=\frac{15}{34}:\frac{3}{2}=\frac{5}{17}\)
a)[(-7)+(-93)]+[(-125)+(-25)
=-100+-150
=-250
b)2012+(-1000)+(-12)+(-500)
=[2012+(-12)]+[(-1000)+(-500)]
=2000+-1500
=-500
c)(-12).7+(-8).7+4.(-25)+(-6).(-25)
=7[(-12)+(-8)]+-25[4+-6]
=7.(-20)+-25.-2
=-140+50
=-90
a) (-7) + (-125) + (-93) + (-25)
= -7 - 125 - 93 - 25
= (-7 - 93) - (125 + 25)
= -100 + (-150)
= -250
b) 2012 + (-1000) + (-12) + (-500)
= (2012 - 12) - (1000 + 500)
= 2000 - 1500
= 500
c) (-12).7 + (-8).7 + 4.(-25) + (-6) . (-25)
= (-12 + (-8) . 7 + (4 + (-6) . (-25)
= -20 .7 + (-2) . (-25)
= -2 . 10 . 7 + (-2) . 25
= -2 . 70 + (-2) . 25
= -2 . (70 + 25)
= -2 . 95
= -190
\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)
a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)
b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)
c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)
d. \(8782-291\cdot13=8782-3783=4999\)
e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)
f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\
a)\(5^{x+2}=125=5^3\\ =>x+2=3\\ =>x=1\)
c)\(5^{2x-1}-2.5^2=3.5^2\\ =>5^{2x-1}=3.5^2+2.5^2\\ =>5^{2x-1}=5^2.\left(3+2\right)=5^2.5=5^3\\ =>2x-1=3\\ =>x=2\)