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Bài làm:
Ta có: \(\frac{9^2.\left(-4\right)^5.72}{5.\left(-6\right)^6}\cdot\frac{6^3.81.\left(-4\right)}{\left(-8\right)^6.3^9}\)
\(=\frac{3^2.-2^{10}.2^3.3^2.2^3.3^3.3^4.-2^2}{5.2^3.3^3.2^{18}.3^9}\)
\(=\frac{2^{18}.3^{11}}{2^{21}.3^{12}.5}\)
\(=\frac{1}{2^3.2.5}=\frac{1}{120}\)
\(\frac{25^5.2^{10}}{20^4.5^4}\)
=\(\frac{25^5.2^{10}}{20^4.25^2}\)
=\(\frac{25^3.2^{10}}{20^4}\)
=\(\frac{25^3.1024}{160000}\)
=\(\frac{25^3.4}{25^2}\)
=\(25.4\)
=100
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a. `17.85+15.17-120`
`=17 . (85+15)-120`
`=17 . 100-120`
`=1700-120`
`=1580`
b. `5.7^2 - 24 : 2^3`
`=5. 49 - 24: 8`
`=245-3`
`=242`
c. `3^3 .22 -27.19`
`=27.22 - 27.19`
`=27 . (22-19)`
`=27.3=81`
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =6^2-15*2
=36-30=6
b: =3*25+15*4-3
=72+60
=132
c: =25*2+5
=50+5
=55
d: =5+12=17
e: =7^2(15-5)=49*10=490
f: =4^3*125-125:25
=1000-5
=995
Ta có: \(A=\dfrac{2^3\cdot5\cdot7\cdot5^2\cdot7^3}{\left(2\cdot5\cdot7^2\right)^2}\)
\(=\dfrac{2^3\cdot5^3\cdot7^4}{2^2\cdot5^2\cdot7^4}=\dfrac{10\cdot2^2\cdot5^2}{2^2\cdot5^2}\)
=10
\(A=\dfrac{(2^3.5.7).(5^2.7^3)}{(2.5.7^2)^2}\)
\(=\dfrac{2^3.5^3.7^4}{2^2.5^2.7^4}\)
\(=2.5\)
\(=10\)