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\(=-5\cdot\dfrac{1}{2}+0-5\cdot\dfrac{6}{5}=-\dfrac{5}{2}-6=-\dfrac{17}{2}\)
\(=\left(\dfrac{3}{2}\cdot\dfrac{2}{5}+2\cdot\dfrac{1}{5}\right):\dfrac{3}{8}=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\cdot\dfrac{8}{3}=\dfrac{8}{3}\)
\(=4\cdot5-2\cdot\dfrac{2}{3}=20-\dfrac{4}{3}=\dfrac{56}{3}\)
a: \(\left(\dfrac{5}{9}-\dfrac{\sqrt{9}}{12}\right):\dfrac{3}{4}+\dfrac{11}{3}:\dfrac{3}{4}\)
\(=\left(\dfrac{5}{9}-\dfrac{3}{12}\right)\cdot\dfrac{4}{3}+\dfrac{11}{3}\cdot\dfrac{4}{3}\)
\(=\left(\dfrac{5}{9}-\dfrac{1}{4}+\dfrac{11}{3}\right)\cdot\dfrac{4}{3}\)
\(=\dfrac{20-9+132}{36}\cdot\dfrac{4}{3}\)
\(=\dfrac{143}{3}\cdot\dfrac{1}{9}=\dfrac{143}{27}\)
b: \(\left(0.\left(3\right)+\dfrac{\left|-2\right|}{3}\right):\dfrac{\sqrt{25}}{4}-\left(2^3+3^2\right)^0\)
\(=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\cdot\dfrac{4}{5}-1\)
\(=\dfrac{4}{5}-1=-\dfrac{1}{5}\)
a. \(\sqrt{35}+\sqrt{99}< \sqrt{36}+\sqrt{100}=6+10=16\)
\(\Rightarrow\sqrt{35}+\sqrt{99}< 16\)
b. \(\sqrt{24}< \sqrt{25}=5\)
\(\sqrt{5}+\sqrt{10}>\sqrt{4}+\sqrt{9}=2+3=5\)
\(\Rightarrow\sqrt{24}< \sqrt{5}+\sqrt{10}\)
Đề dọa trẻ con à
\(\sqrt{x^2\sqrt{x^4\sqrt{x^8\sqrt{x^{16}}}}}=\sqrt{3^{14}}\)
\(\Leftrightarrow\sqrt{x^2\sqrt{x^4\sqrt{x^8\cdot x^8}}}=\sqrt{3^{14}}\)
\(\Leftrightarrow\sqrt{x^2\sqrt{x^4\cdot x^8}}=\sqrt{3^{14}}\)
\(\Leftrightarrow\sqrt{x^2\cdot x^6}=\sqrt{3^{14}}\)
\(\Leftrightarrow x^4=2187\)\(\Rightarrow x=\pm3\sqrt[4]{27}\)
\(=-5\cdot4+0.5-3\cdot\dfrac{4}{5}=-19.5-\dfrac{12}{5}=-\dfrac{219}{10}\)