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3x+17=12
=>3x=12-17
=>3x=-5
=>x=-5:3
=>x=-1,66
/x-1/=0
=>x-1=0
=>x =0+1
=>x =1
-13./x/=-26
=>/x/=-26:(-13)
=>/x/=2
=>x=-2 hoặc x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
3x+17=12
=>3x=12-17
=>3x=-5
=>x=-5:3
=> x=-5/3
vậy x=-5/3
|x-1|=0
=>x-1=0
=>x=0+1
=>x=1
-13.|x|=-26
=>||x|=-26:-13=2
=> x thuộc tập hợp các số -2 hoặc 2
vậy x=2;-2
K nha
![](https://rs.olm.vn/images/avt/0.png?1311)
1,-16+23+x=-16
=>23+x=-16-16
=>23+x=-32
=>x=-32-23
=>x=-55
2,2x-35=15
=>2x=15+35
=>2x=50
=>x=25
3,3x+17=12
=>3x=12-17
=>3x=-5
=>ko có x thỏa mãn
4,|x-1|=0
=>x-1=0
=>x=1
5,-13.|x|=-26
=>|x|=-26:-13
=>|x|=2
=>x=2 hoặc -2
1. -16+23+x=-16
23+x=(-16)-(-16)
23+x=(-16)+16
23+x=0
x=0-23
x=-23
2. 2x-35=15
2x=15+35
2x=50
x=50:2
x=25
3. 3x+17=12
3x=12-17
3x=-5
x=(-5):3
x=-5/3
4. /x-1/=0
/x/=0+1
/x/=1
=>x=1 hoặc x=-1
5. -13./x/=-26
/x/=(-26):(-13)
/x/=2
=>x=2 hoặc x=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
a)-16+23+x=-16
7+x=-16
x=-16-7
x=-23
b)2.x-35=15
2.x=15+35
2.x=50
x=50:2
x=25
c)3.x+17=12
3.x=12-17
3.x=-5
x=-5:3
x=-1,(6)
d)Ix-1I=0
IxI=0+1
IxI=1
=>x=1 hoặc x=-1
e)-13.IxI=-26
IxI=-26:(-13)
IxI=2
=>x=2 hoặc x=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x=-23
b)x=25
c)x=-5/3
d)x=1
e)x=2 hoac x=-2
tk minh nha
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -16 + 23 + x = - 16
23 + x = -16 - (-16)
23 + x = 0
x = 0 - 23
x = -23
Vậy x = -23
b) 2x - 35 = 15
2x = 15 + 35
2x = 50
x = 50 : 2
x = 25
Vậy x = 25
e) -13 . |x| = - 26
|x| = -26 : (-13)
|x| = 2
Vì |-2| = |2| = 2
=> x \(\in\) { 2 ; -2 }
Vậy x \(\in\) {2 ; -2}
Xin lỗi nha ! Câu c và câu d của cậu sai đề rùi nên mình ko làm được!
____________________ SORRY___________________
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
-16+23+x=-16
<=>7+x=-16
<=>x=-16-7
<=>x=-23
Vậy...
2.
2x – 35 = 15
<=>2x=50
<=>x=25
Vậy...
3.
3x + 17 = 12
<=>3x=-5
<=>x=-5/3
Vậy...
4.
│x - 1│= 0
<=>x-1=0
<=>x=1
Vậy..
5.
-13 .│x│ = -26
<=>IxI=2
<=>x=-2 và x=2
Vậy..
![](https://rs.olm.vn/images/avt/0.png?1311)
1) -16 + 23 + x = - 16
ó x = -23
2) 2x – 35 = 15
ó 2x = 50
ó x = 25
3) 3x + 17 = 12
ó 3x = -5
ó x = -5/3
4) │x - 1│= 0
=> x – 1 = 0 ó x = 1
5) -13 .│x│ = -26
ó |x| = 2
ó x = 2 hoặc x = -2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!