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MH
8 tháng 5 2022
+) \(x=32:\dfrac{5}{7}=\dfrac{224}{5}\)
+) \(x=\dfrac{3}{7}\times\dfrac{4}{11}=\dfrac{12}{77}\)
8 tháng 5 2022
1. 5/7 x x =32 =>x=32:5/7=32x7/5=224/5
2. 4/11:x=3/7 =>x=4/11:3/7=4/11x7/3=28/33
DB
5
5 tháng 3 2022
a: 10/3-8/3=2/3
11/4-5/4=6/4=3/2
32/17+21/17=53/17
b: 5/6+7/8=20/24+21/24=41/24
3/7-5/14=6/14-5/14=1/14
7/4-3/5=35/20-12/20=23/20
KS
5 tháng 3 2022
a: 10/3-8/3=2/3
11/4-5/4=6/4=3/2
32/17+21/17=53/17
b: 5/6+7/8=20/24+21/24=41/24
3/7-5/14=6/14-5/14=1/14
7/4-3/5=35/20-12/20=23/20
24 tháng 5 2022
1.\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{8\times3}{33\times4}=\dfrac{8\times12}{11\times12}+\dfrac{8\times3}{33\times4}=\dfrac{8\times15}{132}=\dfrac{120}{132}=\dfrac{10}{11}\)
2.\(\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)
3.\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
`@V.Tr.V`
T
12 tháng 6 2019
#)Giải :
Đặt \(A=\frac{7}{2}+\frac{7}{4}+\frac{7}{8}+\frac{7}{16}+\frac{7}{32}+...+\frac{7}{512}\)
\(A=\frac{7}{2}+\frac{7}{2^2}+\frac{7}{2^3}+\frac{7}{2^4}+...+\frac{7}{2^9}\)
\(\Rightarrow2A=\frac{7}{2^2}+\frac{7}{2^3}+\frac{7}{2^4}+\frac{7}{2^5}+...+\frac{7}{2^{10}}\)
\(\Rightarrow2A-A=\left(\frac{7}{2^2}+\frac{7}{2^3}+\frac{7}{2^4}+\frac{7}{2^5}+...+\frac{7}{2^{10}}\right)-\left(\frac{7}{2}+\frac{7}{2^2}+\frac{7}{2^3}+\frac{7}{2^4}+...+\frac{7}{2^9}\right)\)
\(\Rightarrow A=\frac{7}{2^{10}}-\frac{7}{2}\)
HT
1
H
13 tháng 2 2023
`3/7 + 4/5 + 4/7`
`= (3/7 +4/7)+4/5`
`= 7/7 +4/5`
`= 1 + 4/5`
`= 5/5 +4/5`
`=9/5`
`------`
`6/11 + 2/15 + 5/11`
`=(6/11 + 5/11)+2/15`
`= 1 + 2/15`
`= 15/15 +2/15`
`= 17/15`
`-----`
`4/9 + 2/5 + 15/27`
`= (4/9 + 15/27 )+2/5`
`= 1+2/5`
`=5/5 +2/5`
`=7/5`
`-----`
`6/13 + 9/32 + 21/26`
`= (6/13 + 21/26)+9/32`
`= ( 12/26 + 21/26)+9/32`
`= 33/26 +9/32`
`=645/416`
F
23 tháng 1 2020
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
M
23 tháng 1 2020
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
BT
2
18 tháng 2 2016
7/100+18/21+19/32+1/4+3/21+13/32
=7/100+(18/21+3/21)+(19/32+13/32)
=7/100+ 1 + 1
= 207/100
18 tháng 2 2016
7/100+18/21+19/32+1/4+3/21+13/32
=7/100 + 1/4 + (18/21+3/21)+(19/32+13/32)
=7/100+ 25/100 + 1 + 1
=8/25 + 2
=58/25
= 3/4 : 7/32
= 96/28
\(\left(\dfrac{3}{7}\times\dfrac{7}{4}\right)\times\dfrac{32}{7}=\dfrac{24}{25}\times\dfrac{32}{7}=\dfrac{3}{4}\times\dfrac{32}{7}=\dfrac{24}{7}\)