Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}=\frac{15}{93}\)
\(2.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}\right)=2.\frac{15}{93}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{\left(2x+1\right).\left(2x+3\right)}=\frac{30}{93}\)
\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{2x+1}-\frac{1}{2x+3}=\frac{10}{31}\)
\(\frac{1}{3}-\frac{1}{2x+3}=\frac{10}{31}\)
\(\frac{1}{2x+3}=\frac{1}{3}-\frac{10}{31}\)
\(\frac{1}{2x+3}=\frac{1}{93}\)
=> 2x + 3 = 93
=> 2x = 93 - 3
=> 2x = 90
=> x = 90 : 2
=> x = 45
Vậy x = 45
Ta có (x+1/2)*(2/3-2x)=0
x+\(\frac{1}{2}\) =0 hoặc \(\frac{2}{3}\) -2x=0
x =0-\(\frac{1}{2}\) 2x = \(\frac{2}{3}\)
x =\(-\frac{1}{2}\) x = \(\frac{2}{3}\) : 2 =\(\frac{1}{3}\)
Vậy x =\(-\frac{1}{2}\)hoặc x = \(\frac{1}{3}\)
4^2 + 3^2 - 2^3 .x= 5^2
(4+3)^2-2^3.x=25
7^2-2^3.x=25
49-8.x=25
8.x=49-25
8.x=24
x=24:8
x=3
\(4^2+3^2-2\cdot3x=5^2\)
\(\Leftrightarrow16+9-6x=25\)
\(\Leftrightarrow-6x=25-25\)
\(\Leftrightarrow-6x=0\)
\(\Leftrightarrow x=0\)
a, \(\frac{-17}{12}=\frac{-255}{180}\); \(\frac{31}{18}=\frac{310}{180}\);\(\frac{8}{15}=\frac{96}{180}\)
b, \(\frac{9.6-9.2}{18.5}=\frac{54-18}{90}=\frac{36}{90}=\frac{6}{15}\)
\(\frac{13.2-13.3}{\left(1-14\right).9}=\frac{26-39}{-13.9}=\frac{-13}{-117}=\frac{1}{9}\)
Quy đồng mẫu số \(\frac{6}{15}\)và \(\frac{1}{9}\):
\(\frac{6}{15}=\frac{18}{45}\)
\(\frac{1}{9}=\frac{5}{45}\)
\(.\)
=(1-2)-(3-4)+(5-6)-(7-8)+...+(2021-2022)-2023
=(-1)-(-1)+(-1)-...+(-1)-2023
=0-2023
=-2023
Trả lời:
2x . 22 + 15 = 31
2x . 22 = 31 - 15
2x . 22 = 16
2x . 22 = 24
2x = 24 . 22
2x = 26
=> x = 6
Vậy x = 6.
2x . 22 + 15 = 31
2x . 22 = 31 - 15
2x . 22 = 16
2x . 22 = 24
2x = 24 . 22
2x = 26
x = 6
Vậy x = 6.