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a)\(\left(x+8\right)-11=20-15\)
\(\left(x+8\right)-11=5\)
\( x+8=5+11\)
\(x+8=16\)
\(x=8\)
b) \(2x-\left(3+x\right)=5-7\)
\(2x-\left(3+x\right)=-2\)
\(2x-3-x=-2\)
\(x=1\)
c) \( \left(3x-2^4\right)\times7^5=2\times7^6\)
\(3x-2^4=2\times\left(7^6:7^5\right) \)
\(\left(3x-2^4\right)=2\times7^2\)
\(3x-2^4=2\times49\)
\(3x-16=98\)
\(3x=114\)
\(x=38\)
\(D=4^2+4^3+...+4^{25}\)
\(\Rightarrow4D=4^3+4^4+...+4^{26}\)
\(\Rightarrow3D=4D-D=4^3+4^4+...+4^{26}-4^2-4^3-...-4^{25}=4^{26}-4^2\)
\(\Rightarrow D=\dfrac{4^{26}-4^2}{3}\)
\(|2x-4|-3\left(x-5\right)+1=\) \(0\)\
<=> \(|2x-4|-3x+15+1=0\)
<=> \(|2x-4|=3x-16\)
<=> \(\orbr{\begin{cases}2x-4=3x-16\\2x-4=-3x+16\end{cases}}\)
<=> \(\orbr{\begin{cases}x=12\\x=4\end{cases}}\)
vậy \(x=12\left(h\right)x=4\)
chúc bn học tốt
\(|2x+4|-3\left(x-5\right)+1=0\)\(\Rightarrow|2x+4|-3x+3.5+1=0\)
\(\Rightarrow|2x+4|-3x+15+1=0\)\(\Leftrightarrow|2x+4|-3x+16=0\)
\(\Rightarrow|2x+4|=3x-16\Leftrightarrow\orbr{\begin{cases}2x+4=3x-16\\2x+4=-3x+16\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-3x=4-16\\2x-\left(-3x\right)=4+16\end{cases}}\Leftrightarrow\orbr{\begin{cases}-x=-12\Leftrightarrow x=12\\5x=20\Rightarrow x=4\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=12\\x=4\end{cases}}\)
\(-2\left(2x-8\right)+3\left(4-2x\right)=-72-5\left(3x-7\right)\)
\(-4x+16+12-6x=-72-15x+35\)
\(-4x-6x+15x+28=-72+35\)
\(5x+28=-37\)
\(5x=-65\)
\(x=-13\)
Vậy \(x=-13.\)
-2(2x-8) + 3(4-2x) = -72 - 5(3x - 7)
\(\Leftrightarrow\)-4x +16 +12 - 6x = -72 - 15x + 35
\(\Leftrightarrow\)-4x - 6x +15x = 35 - 72 - 16 - 12
\(\Leftrightarrow\)5x = -65
\(\Leftrightarrow\)x=-13
k cho mk nha :)
\(x.\left(2+8\right)=125-25\)
\(x.10=100\)
\(x=100:10\)
\(x=10\)
Vậy x=10
a) \(\left(2x+1\right)^3=27\)
\(\Leftrightarrow2x+1=3\)
\(\Leftrightarrow x=1\)
b) \(\left(2x-1\right)^3=125\)
\(\Leftrightarrow2x-1=5\)
\(\Leftrightarrow x=3\)
c) \(\left(x+1\right)^4=\left(2x\right)^4\)
\(\Leftrightarrow x+1=2x\)
\(\Leftrightarrow x=1\)
d) \(\left(2x-1\right)^5=x^5\)
\(\Leftrightarrow2x-1=x\)
\(\Leftrightarrow x=1\)
a. ( 2x + 1 )3 = 27
<=> ( 2x + 1 )3 = 33
<=> 2x + 1 = 3
<=> 2x = 2
<=> x = 1
b. ( 2x - 1 )3 = 125
<=> ( 2x - 1 )3 = 53
<=> 2x - 1 = 5
<=> 2x = 6
<=> x = 3
c. ( x + 1 )4 = 2x4
<=> x + 1 = 2x
<=> x = 1
d. ( 2x - 1 )5 = x5
<=> 2x - 1 = x
<=> x = 1
a)\(x-15\%x=\frac{1}{3}\)
\(x.\left(1-15\%\right)=\frac{1}{3}\)
\(x.\frac{-280}{3}=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{-280}{3}\)
\(x=\frac{-1}{280}\)
Vậy \(x=\frac{-1}{280}\)
b)\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{6}{5}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{17}{10}x+\frac{6}{5}=\frac{-5}{6}\)
\(-\frac{17}{10}x=-\frac{5}{6}-\frac{6}{5}\)
\(-\frac{17}{10}x=\frac{-61}{30}\)
\(x=\frac{-61}{30}:\frac{-17}{10}\)
\(x=\frac{61}{51}\)
Vậy \(x=\frac{61}{51}\)
\(\Leftrightarrow2x-x=-25+5\)
\(\Leftrightarrow x=-20\)
\(A=-\frac{5}{7}-\frac{2}{7}+\frac{3}{4}+\frac{1}{4}+-\frac{1}{5}=-1+1-\frac{1}{5}=-\frac{1}{5}\)