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3248 x 246 - 3248 x 123 - 3248 x 23
= 3248 x ( 246 - 123 - 23 )
= 3248 x 100
= 324 800.
Hok tốt!
3248 x 246 - 3248 x 123 - 3248 x 23
= 3248 x ( 246 - 123 -23 )
= 3248 x 100
= 32480
a/ 440 + 2 [ 125 - x ] = 546
==> 2 [ 125 - x ] = 546 - 440
==> 2 [ 125 - x ] 106
==> 125 - x = 106 : 2
==> 125 - x = 53 ==> x = 125 - 53 =72
b/ 7x - 33 = 27 : 24
==> 7x - 27 = 27-4 = 23 = 8
==> 7x = 8+ 27
==> 7x = 35 ==> x = 35 : 7 = 5
c/ [ 12x - 43 ] . 83 = 4 . 84
==> [ 12x - 26 ] . 29 = 22 . 212
==> [ 12x - 26 ] . 29 = 214
==> [ 12x - 26 ] = 214 : 29 = 25
==>. 12x = 25 + 26 = 96
==> x = 96 : 12 = 8
d/ 123 - 5. [ x + 4 ] = 38
==> 5. [ x + 4 ] = 123 - 38
==> 5. [ x + 4 ] = 85
==> x + 4 = 85 : 5
==> x + 4 = 17
==> x = 17 - 4 = 13
e/ [ 2600 + 6400 ] - 3.x = 1200
==> 9000 - 3x = 1200
==> 3x = 9000 -1200 = 7800
==> x = 7800 : 3 = 2600
f/ x2 - 72 : 36 = 23
==> x2 - 2 = 23
==> x2 = 23 + 2
==>x2 = 25
==> x2 = 52
==> x = 5
\(\dfrac{7}{2}+\dfrac{2}{25}=\dfrac{7\times25}{2\times25}+\dfrac{2\times2}{25\times2}=\dfrac{175}{50}+\dfrac{4}{50}=\dfrac{179}{50}\)
\(\dfrac{23}{5}-\dfrac{11}{3}=\dfrac{23\times3}{5\times3}-\dfrac{11\times5}{3\times5}=\dfrac{69}{15}-\dfrac{55}{15}=\dfrac{14}{15}\)
\(\dfrac{3}{7}-\dfrac{1}{14}=\dfrac{3\times2}{7\times2}-\dfrac{1}{14}=\dfrac{6}{14}-\dfrac{1}{14}=\dfrac{5}{14}\)
\(\dfrac{8}{5}:\dfrac{1}{3}=\dfrac{8}{5}\times3=\dfrac{8\times3}{5}=\dfrac{24}{5}\)
\(2:\dfrac{5}{3}=2\times\dfrac{3}{5}=\dfrac{2\times3}{5}=\dfrac{6}{5}\)
\(\dfrac{4}{5}\times\dfrac{7}{15}=\dfrac{4\times7}{5\times15}=\dfrac{28}{75}\)
Lời giải:
\(\frac{7}{2}+\frac{2}{25}=\frac{7\times 25+2\times 2}{2\times 25}=\frac{179}{50}\)
\(\frac{23}{5}-\frac{11}{3}=\frac{23\times 3-5\times 11}{5\times 3}=\frac{14}{15}\)
\(\frac{3}{7}-\frac{1}{14}=\frac{6}{14}-\frac{1}{14}=\frac{6-1}{14}=\frac{5}{14}\)
\(\frac{8}{5}: \frac{1}{3}=\frac{8}{5}\times 3=\frac{24}{5}\)
$2: \frac{5}{3}=\frac{2\times 3}{5}=\frac{6}{5}$
$\frac{4}{5}\times \frac{7}{15}=\frac{28}{75}$
\(\dfrac{\left\{\left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]-5\right\}}{5}=4\\\Rightarrow\left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]-5=20\\ \Leftrightarrow \left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]=25\\\Rightarrow\left(2x-5\right)\cdot23=25+\dfrac{246}{123} =27\\ \Rightarrow2x-5=\dfrac{27}{23}\\\Leftrightarrow 2x=\dfrac{27}{23}+5=\dfrac{142}{23}\\ \Leftrightarrow x=\dfrac{142}{23}:2=\dfrac{71}{23}\)
{[(2xx-5)x23-246:123]-5}:5=4
{[(2xx-5)x23-2]-5}=4x5
{[(2xx-5)x23-2]-5}=20
[(2xx-5)]x23-2]=20+5
[(2xx-5)]x23-2]=25
(2xx-5)x23=25+2
(2xx-5)x23=27
2xx-5=27:23
2xx-5=27/23
2xx=27/23+5
2xx=142/23
x=142/23:2
x=71/23