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28 tháng 7 2023

\(\dfrac{23}{5}-x=-\dfrac{1}{6}+\dfrac{1}{2}\)

\(=>\dfrac{23}{5}-x=\dfrac{1}{3}\)

\(=>x=\dfrac{23}{5}-\dfrac{1}{3}\)

\(=>x=\dfrac{64}{15}\)

\(\dfrac{23}{5}-x=-\dfrac{1}{6}+\dfrac{1}{2}\\ =>\dfrac{23}{5}-x=\dfrac{1}{3}\\ =>x=\dfrac{23}{5}-\dfrac{1}{3}\\ =>x=\dfrac{64}{15}\)

Bài 1: 

Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)

Vậy: \(x=\dfrac{4}{65}\)

Bài 2: 

a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)

\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)

\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)

\(=\dfrac{5366}{527}\)

2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)

3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)

4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)

5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)

6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)

17 tháng 1 2022
64646464646464646464646464646464646464 [more]

1/4+1/3:(2x-1)=-5

-->1/3:(2x-1)=-5-1/4

-->1/3:(2x-1)=-21/4

-->2x-1        =1/3:-21/4

-->2x-1        =-4/63

-->2x           =-4/63+1

-->2x           =59/63

--x               =59/126

b7/9:(2+3/4x)+5/9=23/27

-->7/9:(2+3/4x)     =23/27-5/9

-->7/9:(2+3/4x)     =8/27

-->2+3/4x             =7/9:8/27

-->2+3/4x             =21/8

-->3/4x                 =21/8-2

-->3/4x                 =5/8

-->x                     =5/8:3/4

-->x                     =5/6

c|2x-1/3|+5/6=1

-->|2x-1/3|    =1-5/6

-->|2x-1/3|    =1/6

-->\(\orbr{\begin{cases}2x-\frac{1}{3}=\frac{1}{6}\\2x-\frac{1}{3}=-\frac{1}{6}\end{cases}}\)

-->\(\orbr{\begin{cases}2x=\frac{1}{6}+\frac{1}{3}\\2x=-\frac{1}{6}+\frac{1}{3}\end{cases}}\)

-->\(\orbr{\begin{cases}2x=\frac{1}{2}\\2x=\frac{1}{6}\end{cases}}\)

-->\(\orbr{\begin{cases}x=\frac{1}{2}:2\\x=\frac{1}{6}:2\end{cases}}\)

-->\(\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{1}{12}\end{cases}}\)