K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

17 tháng 4 2020

\(10-\frac{2x}{6}=\frac{27}{5}-x\)

\(-\frac{2x}{6}+x=\frac{27}{5}-10\)

\(-\frac{2x}{6}+\frac{6x}{6}=-\frac{23}{5}\)

\(\frac{2}{3}x=\frac{-23}{5}\)

\(x=\frac{-23}{5}:\frac{2}{3}\)

\(x=\frac{-69}{10}\)

học tốt

a,  \(\frac{\left(5-2x\right)}{3}=\frac{\left(4x-1\right)}{-5}\)

\(\Leftrightarrow-5(5-2x)=3\left(4x-1\right)\)

\(\Leftrightarrow10x-25=12x-3\)

\(\Leftrightarrow10x-12x=25-3\)

\(\Leftrightarrow-2x=22\)

\(\Leftrightarrow x=-11\)

b,  \(\frac{\left(12-3x\right)}{32}=\frac{6}{\left(4-x\right)}\)

\(\Leftrightarrow\frac{3\left(4-x\right)}{32}=\frac{6}{\left(4-x\right)}\)

\(\Leftrightarrow3(4-x)\left(4-x\right)=32.6\)

\(\Leftrightarrow(4-x)\left(4-x\right)=32.2\)

\(\Leftrightarrow(4-x)^2=64\)

\(\Leftrightarrow\orbr{\begin{cases}4-x=8\\4-x=-8\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=12\end{cases}}\)

c,  \(\frac{\left(10-2x\right)}{6}=\frac{27}{\left(5-x\right)}\)

\(\Leftrightarrow\frac{2\left(5-x\right)}{6}=\frac{27}{\left(5-x\right)}\)

\(\Leftrightarrow2(5-x)\left(5-x\right)=27.6\)

\(\Leftrightarrow(5-x)\left(5-x\right)=27.3\)

\(\Leftrightarrow(5-x)^2=81\)

\(\Leftrightarrow\orbr{\begin{cases}5-x=9\\5-x=-9\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=14\end{cases}}\)

1 tháng 10 2020

a, \(\frac{5-2x}{3}=\frac{4x-1}{-5}\Leftrightarrow-25+10x=12x-3\Leftrightarrow-22-2x=0\Leftrightarrow x=-11\)

b, \(\frac{12-3x}{32}=\frac{6}{4-x}\Leftrightarrow\frac{12-3x}{32}=\frac{18}{12-3x}\)

\(\Leftrightarrow\left(12-3x\right)^2=576\Leftrightarrow12-3x=\pm2\)\(\Leftrightarrow\orbr{\begin{cases}x=\frac{10}{3}\\x=\frac{14}{3}\end{cases}}\)

c, \(\frac{10-2x}{6}=\frac{27}{5-x}\Leftrightarrow\frac{10-2x}{6}=\frac{54}{10-2x}\)

\(\Leftrightarrow\left(10-2x\right)^2=324\Leftrightarrow10-2x=\pm18\)\(\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)

24 tháng 12 2017

a,\(\dfrac{2}{3}x-\dfrac{4}{9}=-\dfrac{5}{27}\)

\(\dfrac{2}{3}x=\dfrac{17}{27}\)

\(x=\dfrac{17}{18}\)

b,\(\dfrac{2}{3}x+\dfrac{4}{9}=\dfrac{5}{27}\)

\(\dfrac{2}{3}x=-\dfrac{7}{27}\)

\(x=-\dfrac{7}{18}\)

c,\(x:1,2=5,4:6\)

\(x:1,2=0,9\)

\(x=1,08\)

d,\(1,68:1,2=5,4:x\)

\(1,4=5,4:x\)

\(x=\dfrac{27}{7}\)

e,\(\left(1-2x\right)^2+1=10\)

\(\left(1-2x\right)^2=9\)

\(1-2x=3\)

\(2x=-2\)

\(x=-1\)

f,\(\left(1-2x\right)^2-6=10\)

\(\left(1-2x\right)^2=16\)

\(1-2x=4\)

\(2x=-3\)

\(x=-\dfrac{3}{2}\)

25 tháng 12 2017

đúng ko vậy bạn

6 tháng 9 2021

\(\frac{2x-10}{6}=\frac{-27}{5-x}\)

\(\frac{2\left(x-5\right)}{6}=\frac{27}{x-5}\)

\(2\left(x-5\right)^2=27\times6\)

\(2x^2-20x+50-162=0\)

\(2x^2-20x-112=0\)

\(x^2-10x-56=0\)

\(x^2-14x+4x-56=0\)

\(\left(x-14\right)\left(x+4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-14=0\\x+4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)

KL .....

XIN TIICK

11 tháng 8 2019

\(\frac{10-2x}{6}=\frac{27}{5-x}\)

\(\Rightarrow\frac{2.\left(5-x\right)}{6}=\frac{27}{5-x}\)

\(\Rightarrow\frac{5-x}{3}=\frac{27}{5-x}\)

\(\Rightarrow\left(5-x\right).\left(5-x\right)=3.27\)

\(\Rightarrow\left(5-x\right)^2=81\)

\(\Rightarrow\left(5-x\right)^2=9^2\)

\(\Rightarrow5-x=\pm9\)

\(\Rightarrow\orbr{\begin{cases}5-x=9\\5-x=-9\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-4\\x=14\end{cases}}\)

6 tháng 10 2020

=> (10 - 2x)(5 - x) = 27.6

=> 10(5 - x) - 2x(5 - x) = 162

=> 50 - 10x - 10x + 2x2 = 162

=> 50 - 20x + 2x2 = 162

=> 2(x2 - 10x +25) = 162

=> x2 - 10x + 25 = 81

=> x2 - 2.x.5 + 52 = 81

=> (x - 5)= 81

=> (x - 5)2 = (\(\pm\)9)2

+) x + 5 = 9 => x = 4

+) x + 5 = -9 => x = -14

6 tháng 10 2020

Tìm x 

\(\frac{10-2x}{6}=\frac{27}{5-x}\Leftrightarrow\left(10-2x\right)\left(5-x\right)=6.27\)

\(\Leftrightarrow10\left(5-x\right)-2x\left(5-x\right)=162\)

\(\Leftrightarrow50-10x-10x+2x^2=162\)

\(\Leftrightarrow50-20x+2x^2=126\)

\(\Leftrightarrow2\left(x^2-10x+25\right)=162\)

\(\Leftrightarrow\left(x-5\right)^2=162:2\)

\(\Leftrightarrow\left(x-5\right)^2=81\)

\(\Leftrightarrow\hept{\begin{cases}x-5=9\\x-5=-9\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=4\\x=-14\end{cases}}\)

1 tháng 8 2018

a)     \(5-\frac{2x}{3}=4x-\frac{1}{-5}\)

   \(\frac{75-10x}{15}=\frac{60x+3}{15}\)

     75   -  10x    =   60x   +3 

      72               = 70x

       \(\frac{72}{70}\)   =  x

     x               =\(\frac{36}{35}\)

Vậy   x  =    \(\frac{36}{35}\)

b)    \(2x-\frac{10}{6}=\frac{-27}{5}-x\)

      \(2x-\frac{5}{3}=\frac{-27}{5}-x\)

        \(\frac{30x-25}{15}=\frac{-81-15}{15}\)

         30x              =-96+25

          30x                 =-71

             x=   -71/30

Vậy x= -71/30

c)    \(13x-\frac{2}{2x}+5=\frac{76}{17}\)

         13x  -  1/x   +5    =   76/17

        \(\frac{221x-17+85}{17x}=\frac{76x}{17x}\)

         221x   +68   = 76x

         221x-76x        =-68

         145x               =-68

               x                =\(\frac{-68}{145}\)

Vậy .........

        

25 tháng 6 2019

\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8-6^8.20}\)

\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8-\left(2.3\right)^8.2^2.5}\)

\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8-2^{10}.3^8.5}\)

\(A=\frac{2^{10}.\left(3^8-3^9\right)}{2^{10}.3^8.\left(1-5\right)}=\frac{3^8-3^9}{3^8.\left(-4\right)}=\frac{3^8.\left(1-3\right)}{3^8.\left(-4\right)}=\frac{-2}{-4}=\frac{1}{2}\)

Vậy A = \(\frac{1}{2}\)

\(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(B=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)

\(B=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(B=\frac{2^{19}.3^9+3^9.2^{18}.5}{2^{19}.3^9+2^{20}.3^{10}}\)

\(B=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9\left(1+2.3\right)}=\frac{7}{2.7}=\frac{1}{2}\)

Vậy B = \(\frac{1}{2}\)

2 tháng 8 2018

\(\frac{5-2x}{3}=\frac{4x-1}{-5}\)

-5(5-2x) = 3(4x-1)

-25 + 10x = 12x - 3

10x - 12x = -3 + 25

-2x = 22

x= -11

Nhân chéo như trên rồi tự làm nha

Học tốt~