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a) \(-\frac{3}{4}-\left(x+\frac{1}{2}\right)=1\frac{2}{3}=\frac{5}{3}\Leftrightarrow-\left(x+\frac{1}{2}\right)=\frac{5}{3}+\frac{3}{4}=\frac{29}{12}\)
\(\Leftrightarrow x+\frac{1}{2}=-\frac{29}{12}\Leftrightarrow x=-\frac{29}{12}-\frac{1}{2}=-\frac{29}{12}-\frac{6}{12}=-\frac{35}{12}\)
b) \(3,15:0,4=2,1x:1,68\Leftrightarrow7,875=2,1x\div1,68\Leftrightarrow2,1x=7,875\times1,68=13,23\)
\(\Leftrightarrow x=13,23\div2,1\Leftrightarrow x=6,3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(2,1x+\frac{5}{3}\right)^6=\left(-3,2x+\frac{1}{2}\right)^6\Rightarrow2,1x+\frac{5}{3}=-3,2x+\frac{1}{2}\)
\(\Rightarrow2,1x+3,2x=\frac{1}{2}-\frac{5}{3}\)
\(5,3x=\frac{-7}{6}\)
\(x=\frac{-7}{6}:\frac{53}{10}=\frac{-35}{159}\)
Vậy \(x=\frac{-35}{159}\)
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a ) Ta có : \(\left|x\right|=2\frac{1}{3}\)
Đổi : \(2\frac{1}{3}=\frac{7}{3}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{7}{3}\\x=-\frac{7}{3}\end{array}\right.\)
Kết luận : \(x\in\left\{\frac{7}{3};-\frac{7}{3}\right\}\)
b ) \(\left|x\right|=-3\)
Vì : \(x< 0\)
\(\Rightarrow x\) không thõa mãn
Kết luận : \(x\in\left\{\varnothing\right\}\)
c ) \(\left|x\right|=-3,15\)
Vì : \(x< 0\)
\(\Rightarrow x\) không thõa mãn
Kết luận : \(x\in\left\{\varnothing\right\}\)
d ) \(\left|x-1,7\right|=2,3\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1,7=2,3\\x-1,7=-2,3\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=4\\x=-0,6\end{array}\right.\)( thõa mãn )
Kết luận : \(x\in\left\{4;-0,6\right\}\)
e ) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)
\(\left|x+\frac{3}{4}\right|=\frac{1}{2}\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{array}\right.\)
Kết luận \(x\in\left\{-\frac{1}{4};-\frac{5}{4}\right\}\)
\(a,\left|x\right|=2\frac{1}{3}\Rightarrow\left|x\right|=\frac{7}{3}\)
\(\Rightarrow\) \(\begin{cases}x=\frac{7}{3}\\x=\frac{-7}{3}\end{cases}\)
\(b,\left|x\right|=-3\) ( Vì |x| < 0 ) \(\Rightarrow x\in\varnothing\)
\(c,\left|x\right|=-3,15\) (Vì \(\left|x\right|< 0\) ) \(\Rightarrow x\in\varnothing\)
\(d,\left|x-1,7\right|=2,3\)
\(\Rightarrow\) \(\begin{cases}x-1,7=2,3\\x-1,7=-2,3\end{cases}\) \(\Rightarrow\) \(\begin{cases}x=2,3+1,7\\x=-2.3+1,7\end{cases}\) \(\Rightarrow\) \(\begin{cases}x=4\\x=-0,6\end{cases}\)
\(e,\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)
\(\Rightarrow\left|x+\frac{3}{4}\right|=\frac{1}{2}\) \(\Rightarrow\) \(\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{cases}\) \(\Rightarrow\) \(\begin{cases}x=\frac{1}{2}-\frac{3}{4}=-\frac{1}{4}\\x=-\frac{1}{2}-\frac{3}{4}=-\frac{5}{4}\end{cases}\)
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\(\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{13}}{\frac{2}{3}-0,4-\frac{2}{15}}=\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{5}-\frac{2}{15}}=\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{13}}{2\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{15}\right)}\)
đề sai hay sao ý bạn, chỗ \(\frac{1}{13}\)và\(\frac{2}{15}\)ý
Linh bạn tham khảo bài của mk nhé , mk sửa bài cho bạn rồi nhé :vv
Tính nhanh:
\(\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{15}}{\frac{2}{3}-0,4-\frac{2}{15}}\)
Giải:
\(\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{15}}{\frac{2}{3}-0,4-\frac{2}{15}}=\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{15}}{\frac{2}{3}-\frac{2}{5}-\frac{2}{15}}=\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{15}}{2\left[\frac{1}{3}-\frac{1}{5}-\frac{1}{15}\right]}=\frac{1}{2}\)
Vậy đáp án của bài toán này là 1/2
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\(\frac{1}{3}x-\frac{3}{5}=\frac{5}{6}x+2\)
\(\Leftrightarrow\frac{x}{3}-\frac{3}{5}=\frac{5x}{6}+2\)
\(\Leftrightarrow2x-\frac{18}{5}=5x+12\)
\(\Leftrightarrow2x-5x=\frac{18}{5}+12\)
\(\Leftrightarrow-3x=\frac{78}{5}\)
\(\Leftrightarrow3x=-\frac{78}{5}\)
\(\Leftrightarrow x=-\frac{26}{5}\)
Ps: đoạn nào không hiểu hỏi anh nhé. Nhớ k để tạo động lực cho anh nhé :33
# Aeri #
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a) Cách 1:
\(\begin{array}{l}(8 + 2\frac{1}{3} - \frac{3}{5}) - (5 + 0,4) - (3\frac{1}{3} - 2)\\ = (8 + \frac{7}{3} - \frac{3}{5}) - (5 + \frac{4}{{10}}) - (\frac{{10}}{3} - 2)\\ = 8 + \frac{7}{3} - \frac{3}{5} - 5 - \frac{2}{5} - \frac{{10}}{3} + 2\\ = (8 - 5 + 2) + (\frac{7}{3} - \frac{{10}}{3}) - (\frac{3}{5} + \frac{2}{5})\\ = 5 + \frac{{ - 3}}{3} - \frac{5}{5}\\ = 5 + ( - 1) - 1\\ = 3\end{array}\)
Cách 2:
\(\begin{array}{l}(8 + 2\frac{1}{3} - \frac{3}{5}) - (5 + 0,4) - (3\frac{1}{3} - 2)\\ = (8 + \frac{7}{3} - \frac{3}{5}) - (5 + \frac{4}{{10}}) - (\frac{{10}}{3} - 2)\\ = (\frac{{120}}{{15}} + \frac{{35}}{{15}} - \frac{9}{{15}}) - (\frac{{25}}{5} + \frac{2}{5}) - (\frac{{10}}{3} - \frac{6}{3})\\ = \frac{{146}}{{15}} - \frac{{27}}{5} - \frac{4}{3}\\ = \frac{{146}}{{15}} - \frac{{81}}{{15}} - \frac{{20}}{{15}}\\ = \frac{{45}}{{15}}\\ = 3\end{array}\)
b)
\(\begin{array}{l}(7 - \frac{1}{2} - \frac{3}{4}):(5 - \frac{1}{4} - \frac{5}{8})\\ = (\frac{{28}}{4} - \frac{2}{4} - \frac{3}{4}):(\frac{{40}}{8} - \frac{2}{8} - \frac{5}{8})\\ = \frac{{23}}{4}:\frac{{33}}{8}\\ = \frac{{23}}{4}.\frac{8}{{33}}\\ = \frac{{46}}{{33}}\end{array}\)
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1. a) \(\frac{3}{4}-\frac{-1}{2}+\frac{1}{3}=\frac{3}{4}+\frac{1}{2}+\frac{1}{3}=\frac{9}{12}+\frac{6}{12}+\frac{4}{12}=\frac{19}{12}\)
b) \(5\frac{5}{27}+\frac{7}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}\)
\(=\frac{140}{27}-\frac{5}{27}+\frac{7}{23}+\frac{16}{23}+\frac{1}{2}\)
\(=\frac{135}{27}+\frac{23}{23}+\frac{1}{2}\)
\(=5+1+0,5=6,5\)
2) a) 1/2 + 2/3x = 1/4
=> 2/3x = 1/4 - 1/2
=> 2/3x = -1/4
=> x = -1/4 : 2/3
=> x = -3/8
b) 3/5 + 2/5 : x = 3 1/2
=> 3/5 + 2/5 : x = 7/2
=> 2/5 : x = 7/2 - 3/5
=> 2/5 : x = 29/10
=> x = 2/5 : 29/10
=> x = 4/29
c) x+4/2004 + x+3/2005 = x+2/2006 + x+1/2007
=> x+4/2004 + 1 + x+3/2005 + 1 = x+2/2006 + 1 + x+1/2007 + 1
=> x+2008/2004 + x+2008/2005 = x+2008/2006 + x+2008/2007
=> x+2008/2004 + x+2008/2005 - x+2008/2006 - x+2008/2007 = 0
=> (x+2008). (1/2004 + 1/2005 - 1/2006 - 1/2007) = 0
Vì 1/2004 + 1/2005 - 1/2006 - 1/2007 khác 0
Nên x + 2008 = 0 <=> x = -2008
Vậy x = -2008
1,a,\(\frac{3}{4}-\frac{-1}{2}+\frac{1}{3}=\frac{3}{4}+\frac{2}{4}+\frac{1}{3}=\frac{5}{4}+\frac{1}{3}=\frac{15}{12}+\frac{4}{12}=\frac{19}{12}\)
b, \(5\frac{5}{27}+\frac{7}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}=\frac{140}{27}-\frac{5}{27}+\frac{7}{23}+\frac{16}{23}+\frac{1}{2}=\frac{135}{27}+\frac{23}{23}+\frac{1}{2}=5+1+\frac{1}{2}=\frac{13}{2}\)2,a,\(\frac{1}{2}+\frac{2}{3}.x=\frac{1}{4}\)
<=>\(\frac{2}{3}.x=-\frac{1}{2}\)
<=>\(x=-\frac{3}{4}\)
b,\(\frac{3}{5}+\frac{2}{5}\div x=3\frac{1}{2}\)
<=>\(\frac{2}{5x}=\frac{29}{10}\)
<=>\(x=\frac{29}{4}\)
c,\(\frac{x+4}{2004}+\frac{x+3}{2005}=\frac{x+2}{2006}+\frac{x+1}{2007}\)
<=> \(\frac{x+4}{2004}+1+\frac{x+3}{2005}+1=\frac{x+2}{2006}+1+\frac{x+1}{2007}+1\)
<=>\(\frac{x+2008}{2004}+\frac{x+2008}{2005}=\frac{x+2008}{2006}+\frac{x+2008}{2007}\)
<=>\(\left(x+2008\right)\left(\frac{1}{2004}+\frac{1}{2005}-\frac{1}{2006}-\frac{1}{2007}\right)\)=0
<=>x+2008=0 vì cái ngoặc còn lại\(\ne0\)
<=>x=-2008
Vậy x=-2008
Bạn nhớ tk cho mình vì mình đã chăm chỉ làm hết bài bạn hỏi nha!
\(x-3\frac{1}{2}=\frac{3}{5}\)
\(x=\frac{3}{5}+3\frac{1}{2}\)
\(x=4\frac{1}{10}\)
Vậy x = \(4\frac{1}{10}\)
Nhớ k cho mình nhé! Thank you!!!
\(3,15\div0,4=2,1.x\div1,68\)
\(7,875=2,1.x\div1,68\)
\(2,1.x=7,875\times1,68\)
\(2,1.x=13,23\)
\(x=13,23\div2,1\)
\(x=6,3\)
Vậy x = 6,3
Nhớ k cho mình nhé! Thank you!!!